无论我如何编辑程序,似乎都存在溢出错误和不匹配的类型错误。有人可以帮我做这个没有错误的运行。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
int choice;
int i;
int j;
char type;
int amount;
int don_count = 0;
int req_count = 0;
int flag;
char donations_inv_type[100][20];
int donations_amount[100];
char requests_inv_type[100][20];
int req_amount[100];
printf("Welcome to the Food Bank Program\n\n 1. Add a donation\n 2. Add a request\n 3. Fulfill a request\n 4. Print status report\n 5. Exit\n\nEnter your choice: ");
scanf("%d", &choice);
while (choice != 5) {
if (choice == 1) {
printf("\nEnter inventory type: ");
scanf("%s", &type);
printf("Enter the amount: ");
scanf("%d", &amount);
printf("\nDonation Added!\n\n");
flag = -99;
for (i = 0; i < don_count; i++) {
if (strcmp(donations_inv_type[i], type) == 0)
flag = i;
}
if (flag == -99) {
strcpy(donations_inv_type[i], type);
donations_amount[i] = amount;
don_count++;
}
else
donations_amount[flag] += amount;
printf("Donation Added!\n");
printf("Press any key to continue . . .\n\n");
}
else if (choice == 2) {
printf("\nEnter inventory type: ");
scanf("%s", &type);
printf("Enter the amount: ");
scanf("%d", &amount);
strcpy(requests_inv_type[req_count], type);
req_amount[req_count] = amount;
req_count++;
}
else if (choice == 3) {
printf("\n\n-------- Fulfilling Requests--------");
flag = -99;
for (i = 0; i < don_count; i++) {
if (strcmp(donations_inv_type[i], requests_inv_type[0]) == 0)
flag = i;
}
if (flag == -99)
printf("Cannot be Fulfilled\n\n");
else if (donations_amount[flag] > req_amount[0]) {
donations_amount[flag] -= req_amount[0];
printf("Request Fulfilled");
req_amount[0] = 0;
}
else if (donations_amount[flag] == req_amount[0]) {
printf("Request Fulfilled");
for (i = flag; i < don_count; i++) {
strcpy(donations_inv_type[i], donations_inv_type[i + 1]);
strcpy(donations_amount[i], donations_amount[i + 1]);
}
don_count--;
for (i = flag; i < req_count; i++) {
strcpy(requests_inv_type[i], requests_inv_type[i + 1]);
strcpy(req_amount[i], req_amount[i + 1]);
}
req_count--;
}
else if (donations_amount[flag] < req_amount[0]) {
printf("Partially Fulfilled");
req_amount[0] -= donations_amount[flag];
for (i = flag; i < don_count; i++) {
strcpy(donations_inv_type[i], donations_inv_type[i + 1]);
strcpy(donations_amount[i], donations_amount[i + 1]);
don_count--;
}
}
}
else if (choice == 4) {
printf("Printing the Donations Table\n\n");
for (i = 0; i < don_count; i++) {
printf("%s %d", donations_inv_type[i], donations_amount[i]);
}
printf("Printing the Requests Table\n\n");
for (i = 0; i < req_count; i++) {
printf("%s %d", requests_inv_type[i], req_amount[i]);
}
}
printf("Welcome to the Food Bank Program\n\n 1. Add a donation\n 2. Add a request\n 3. Fulfill a request\n 4. Print status report\n 5. Exit\n\nEnter your choice: ");
}
}
非常感谢任何帮助,我希望能解释一下我做错了什么,以便我可以学习并且下次不会犯同样的错误。
答案 0 :(得分:2)
而不是char type
您需要char type[100]
代码出错:
if (strcmp(donations_inv_type[i], type) == 0)
// ^^^^ should be char*
注意:函数strcmp()
和strcpy()
应该传递\0
以空字符结尾的char数组(或者说字符串)。
您的scanf应该看起来像scanf("%s", type);
答案 1 :(得分:2)
将type
声明为character array
。
char type[50];
删除&
中的scanf()
。阅读字符串时不应使用&
。
scanf("%s", &type); ==> scanf("%s", type);
^
在这里你要复制整数而不是字符串
strcpy(donations_amount[i], donations_amount[i + 1]);
strcpy(req_amount[i], req_amount[i + 1]);
像这样修改
donations_amount[i]=donations_amount[i + 1];
req_amount[i]= req_amount[i + 1];