我目前正在实施基于Stop-and-Wait协议的UDP服务器和客户端。服务器端完成后,我还没有开始做客户端。我希望先测试我的服务器。
#include "headsock.h"
void str_ser(int sockfd); // transmitting and receiving function
int main(int argc, char *argv[])
{
int sockfd;
struct sockaddr_in my_addr;
//create socket
if ((sockfd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
printf("error in socket\n");
exit(1);
}
my_addr.sin_family = AF_INET; // Address family; must be AF_INET
my_addr.sin_port = htons(MYUDP_PORT); // Internet Protocol (IP) port.
my_addr.sin_addr.s_addr = INADDR_ANY; // IP address in network byte order. INADDR_ANY is 0.0.0.0 meaning "all the addr"
// places nbyte null bytes in the string s. This function will be used to set all the socket structures with null values.
bzero(&(my_addr.sin_zero), 8);
// binds the socket to all available interfaces
if (bind(sockfd, (struct sockaddr *) &my_addr, sizeof(struct sockaddr)) == -1) {
printf("error in binding\n");
perror("socket error");
exit(1);
}
while (1)
{
str_ser(sockfd); // send and receive
}
close(sockfd);
exit(0);
}
void str_ser(int sockfd) // transmitting and receiving function
{
FILE *fp;
char buf[BUFSIZE];
char recvs[DATALEN];
int end, n = 0;
long lseek=0;
struct ack_so ack;
struct sockaddr_in addr;
socklen_t len = sizeof(struct sockaddr_in);
printf("receiving data!\n");
while(!end)
{
// receive the packet
if ((n = recvfrom(sockfd, &recvs, DATALEN, 0, (struct sockaddr *)&addr, &len)) == -1)
{
printf("error when receiving\n");
exit(1);
}
// if it is the EoF
if (recvs[n-1] == '\0')
{
end = 1;
n--;
}
memcpy((buf+lseek), recvs, n);
lseek += n;
// up to here, successfully received a packet
// send ACK back
ack.num = 1;
ack.len = 0;
if ((n = sendto(sockfd, &ack, ack.len, 0, (struct sockaddr *)&addr, len)) == -1)
{
printf("ACK send error!\n");
exit(1);
}
}
if ((fp = fopen ("myUDPreceive.txt", "wt")) == NULL)
{
printf("File doesn't exit\n");
exit(0);
}
fwrite (buf , 1 , lseek , fp); //write data into file
fclose(fp);
printf("A file received!\nThe total data received is %d bytes\n", (int)lseek);
}
当我运行服务器时,由于当前没有客户端,我希望看到服务器被困在while(!end)
循环中。但是,当我运行它时,我最终得到了这个:
receiving data!
A file received!
The total data received is 0 bytes
receiving data!
A file received!
The total data received is 0 bytes
receiving data!
A file received!
The total data received is 0 bytes
receiving data!
A file received!
The total data received is 0 bytes
receiving data!
这意味着EoF Checker代码段
// if it is the EoF
if (recvs[n-1] == '\0')
{
end = 1;
n--;
}
已被执行。
但我在那里没有客户!为什么会这样?
答案 0 :(得分:1)
int end, n = 0;
初始化n
但不是end
,表示测试
while(!end)
几乎肯定会失败。您需要显式初始化两个变量
int end = 0, n = 0;