滚动data.table同时向前和向后

时间:2013-10-08 16:14:06

标签: r data.table

这与之前关于SO的问题有关:roll data.table with rollends

鉴于数据......

library(data.table)

dt1 = data.table(Date=seq(from=as.Date("2013-01-03"),
                      to=as.Date("2013-06-27"), by="1 week"),
             key="Date")[, ind:=.I]
dt2 = data.table(Date=seq(from=as.Date("2013-01-01"),
                      to=as.Date("2013-06-30"), by="1 day"),
             key="Date")

我尝试提前一天带来每周数据点 ......

dt1[dt2, roll=1][dt2, roll=-1]

...但只有第一次滚动加入(转发)似乎有效且roll=-1被忽略:

           Date ind
  1: 2013-01-01  NA
  2: 2013-01-02  NA
  3: 2013-01-03   1
  4: 2013-01-04   1
  5: 2013-01-05  NA
 ---               
177: 2013-06-26  NA
178: 2013-06-27  26
179: 2013-06-28  26
180: 2013-06-29  NA
181: 2013-06-30  NA

当我颠倒订单时效果相同:

dt1[dt2, roll=-1][dt2, roll=1]

           Date ind
  1: 2013-01-01  NA
  2: 2013-01-02   1
  3: 2013-01-03   1
  4: 2013-01-04  NA
  5: 2013-01-05  NA
 ---               
177: 2013-06-26  26
178: 2013-06-27  26
179: 2013-06-28  NA
180: 2013-06-29  NA
181: 2013-06-30  NA

我想实现:

           Date ind
  1: 2013-01-01  NA
  2: 2013-01-02   1
  3: 2013-01-03   1
  4: 2013-01-04   1
  5: 2013-01-05  NA
 ---               
177: 2013-06-26  26
178: 2013-06-27  26
179: 2013-06-28  26
180: 2013-06-29  NA
181: 2013-06-30  NA

修改 我使用的是新的 data.table版本1.8.11 ,请注意会话详细信息:

sessionInfo()

R version 3.0.0 (2013-04-03)
Platform: x86_64-w64-mingw32/x64 (64-bit)

locale:
[1] LC_COLLATE=English_United Kingdom.1252  LC_CTYPE=English_United Kingdom.1252   
[3] LC_MONETARY=English_United Kingdom.1252 LC_NUMERIC=C                           
[5] LC_TIME=English_United Kingdom.1252    

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

other attached packages:
[1] data.table_1.8.11

loaded via a namespace (and not attached):
[1] plyr_1.8       reshape2_1.2.2 stringr_0.6.2  tools_3.0.0   

由于

1 个答案:

答案 0 :(得分:4)

第一次加入后无法滚动,dt2 中的每一行都有 dt1[dt2, roll = .]中的相应行。因此,只需将两个卷分开进行组合,例如:

dt1[dt2, roll = 1][, ind := ifelse(is.na(ind), dt1[dt2, roll = -1]$ind, ind)]