这与之前关于SO的问题有关:roll data.table with rollends
鉴于数据......
library(data.table)
dt1 = data.table(Date=seq(from=as.Date("2013-01-03"),
to=as.Date("2013-06-27"), by="1 week"),
key="Date")[, ind:=.I]
dt2 = data.table(Date=seq(from=as.Date("2013-01-01"),
to=as.Date("2013-06-30"), by="1 day"),
key="Date")
我尝试提前一天带来每周数据点 ......
dt1[dt2, roll=1][dt2, roll=-1]
...但只有第一次滚动加入(转发)似乎有效且roll=-1
被忽略:
Date ind
1: 2013-01-01 NA
2: 2013-01-02 NA
3: 2013-01-03 1
4: 2013-01-04 1
5: 2013-01-05 NA
---
177: 2013-06-26 NA
178: 2013-06-27 26
179: 2013-06-28 26
180: 2013-06-29 NA
181: 2013-06-30 NA
当我颠倒订单时效果相同:
dt1[dt2, roll=-1][dt2, roll=1]
Date ind
1: 2013-01-01 NA
2: 2013-01-02 1
3: 2013-01-03 1
4: 2013-01-04 NA
5: 2013-01-05 NA
---
177: 2013-06-26 26
178: 2013-06-27 26
179: 2013-06-28 NA
180: 2013-06-29 NA
181: 2013-06-30 NA
我想实现:
Date ind
1: 2013-01-01 NA
2: 2013-01-02 1
3: 2013-01-03 1
4: 2013-01-04 1
5: 2013-01-05 NA
---
177: 2013-06-26 26
178: 2013-06-27 26
179: 2013-06-28 26
180: 2013-06-29 NA
181: 2013-06-30 NA
修改 我使用的是新的 data.table版本1.8.11 ,请注意会话详细信息:
sessionInfo()
R version 3.0.0 (2013-04-03)
Platform: x86_64-w64-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_United Kingdom.1252 LC_CTYPE=English_United Kingdom.1252
[3] LC_MONETARY=English_United Kingdom.1252 LC_NUMERIC=C
[5] LC_TIME=English_United Kingdom.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] data.table_1.8.11
loaded via a namespace (and not attached):
[1] plyr_1.8 reshape2_1.2.2 stringr_0.6.2 tools_3.0.0
由于
答案 0 :(得分:4)
第一次加入后无法滚动,dt2
中的每一行都有 dt1[dt2, roll = .]
中的相应行。因此,只需将两个卷分开进行组合,例如:
dt1[dt2, roll = 1][, ind := ifelse(is.na(ind), dt1[dt2, roll = -1]$ind, ind)]