Question

我有一个小脚本，可以对两个隐藏的输入字段进行多重检查：

    function checkfs()
{ 
var rating1 = (document.getElementById("rating").value);
var rating2 = (document.getElementById("rating").value);
var rating3 = (document.getElementById("rating").value);
var check1 = (document.getElementById("countpl").value);
var check2 = (document.getElementById("countpl").value);
var check3 = (document.getElementById("countpl").value);

    if (rating3 == 3 && check3 > 22 || check3 < 19){
        alert("message 1");
        window.location.href = 'myteam.php';}

else if (rating2 == 2 && check2 > 21 || check2 < 18){
        alert("message 2");
        window.location.href = 'myteam.php';}

else if (rating1 == 1 && check1 > 20 || check1 < 17){
        alert("message 3");
        window.location.href = 'myteam.php';}       

else {return true;}    
    }    
    window.onload = checkfs;

HTML

    <input name="countpl" id="countpl" type="hidden" value="<?php echo $row_checkfs['count(f_player.id)']; ?>"/>
<input name="rating" id="rating" type="hidden" value="<?php echo $row_checkfs['rating']; ?>"/>

我无法理解如何根据已经进行的控制类型可视化正确的警报。目前我总是看到“警告（”消息1“）”“无论发现什么问题。如果rating3 == 3＆amp;＆amp ;;我希望消息1出现check3＆gt; 22 || check3＆lt; 19，如果rating2 == 2＆amp;＆amp ;;则出现消息2 check2＆gt; 21 || check2＆lt; 18等如何修改代码才能获得此结果？

Answer 1

试试这个：

function checkfs()
{ 
var rating = (document.getElementById("rating").value);
var check = (document.getElementById("countpl").value);
alert("rating="+rating+" - Check="+check);
    if (rating == 3 && (check > 22 || check < 19)){
        alert("message 1");
        window.location.href = 'myteam.php';}

else if (rating == 2 && (check > 21 || check < 18)){
        alert("message 2");
        window.location.href = 'myteam.php';}

else if (rating == 1 && (check > 20 || check < 17)){
        alert("message 3");
        window.location.href = 'myteam.php';}       

else {return true;}    
    }

我添加了一个警报以查看实际值。

我还使用了2个变量而不是6个，并在“或”条件中添加了括号。

我认为失败的主要原因是“或”条件下的括号。

您应该查看有关运营商优先权的理论。

Answer 2

试

<script>
function checkfs()
{ 
var rating = (document.getElementById("rating").value);
var check = (document.getElementById("countpl").value);

if (rating == 3 && (check > 22 || check < 19)){
alert("message 1");
window.location.href = 'myteam.php';
}

else if (rating == 2 && (check > 21 || check < 18)){
alert("message 2");
window.location.href = 'myteam.php';
}

else if (rating == 1 && (check > 20 || check < 17)){
alert("message 3");
window.location.href = 'myteam.php';
}

else {return true;}    
}    
window.onload = checkfs;
</script>

Answer 3

还考虑将函数用于重复性任务，

function checkfs()
{ 
    var rating = (document.getElementById("rating").value);
    var check = (document.getElementById("countpl").value);
    alert("rating="+rating+" - Check="+check);
    if (rating == 3 && checkThis(check,19,22)){
        alert("message 1");
        window.location.href = 'myteam.php';}

    else if (rating == 2 && checkThis(check,18,21)){
        alert("message 2");
        window.location.href = 'myteam.php';}

    else if (rating == 1 && checkThis(check,17,20)){
        alert("message 3");
        window.location.href = 'myteam.php';}       

    else {return true;}    
} 

function checkThis(tocheck, min, max)
{
   return tocheck<min || tocheck>max;
}

多个警报Javascript

3 个答案: