通过用户昵称获取steamID

时间:2013-10-08 12:36:53

标签: php steam-web-api

是否可以通过他的昵称获取用户的steamID?我没有在steam API文档中找到解决方案。我找到的唯一一件事是http://dev.dota2.com上的旧帖子:

  

您可以使用此功能直接使用GetMatchHistory的player_name选项搜索D​​ota2 API   然后,您可以在列表中找到它们的32位ID,然后将其转换为64位ID。

但现在GetMatchHistory函数没有player_name参数。现在它需要account_id

那么http://dotabuff.com/search?q=Dendi等网站如何获取此信息?

5 个答案:

答案 0 :(得分:13)

您可以使用

获取http://api.steampowered.com/ISteamUser/ResolveVanityURL/v0001/

从Steam配置文件的自定义网址获取SteamID。见http://wiki.teamfortress.com/wiki/WebAPI/ResolveVanityURL

您无法从某人的当前昵称获取steamID,因为昵称可能会发生变化并且不是唯一的。

答案 1 :(得分:1)

使用PHP和Steam Condenser项目,您可以完成此任务。

require_once('steam/steam-condenser.php');

$playername = 'NAMEOFPLAYER';
try
{
    $id = SteamId::create($playername);
} 
catch (SteamCondenserException $s)
{
    // Error occurred
}

echo $id->getSteamId;

如果您需要更多信息,项目的Wiki中有usage examples

答案 2 :(得分:0)

这是我解决这个问题的方法:

module.exports.getProfile = async (req, res) => {
let response = { success: false, data: {}, error: {} }
let { profileAddress } = req.body;
if (profileAddress) {
    try {
        let steamId;
        let split = profileAddress.split('/');
        split = split.filter(arrayItem => arrayItem != '');
        if (split[split.length - 2] === 'profiles') {
            steamId = split[split.length - 1]
        } else {
            let vanityUrl = split[split.length - 1];
            let steamIdResponse = await axios.get(
                `http://api.steampowered.com/ISteamUser/ResolveVanityURL/v0001/?key=${process.env.steamApiKey}&vanityurl=${vanityUrl}`,
            );
            if (steamIdResponse.data.response.success === 1) {
                steamId = steamIdResponse.data.response.steamid;
            } else {
                response.error = steamIdResponse.data.response.message;
            }
        }
        let profileResponse = await axios.get(
            `http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=${process.env.steamApiKey}&steamids=${steamId}`,
        );
        if (profileResponse.data.response.players[0]) {
            response = {
                success: true,
                data: profileResponse.data.response.players[0],
                error: null
            }
            res.status(200);
        } else {
            response.error = response.error ? response.error : "Failed to get Profile.";
            res.status(500);
        }
        res.send(response);
    } catch (error) {
        console.log(error)
        response.error = "Failed to get Profile."
        res.status(500).send(response);
    }
} else {
    response.error = "Profile URL missing."
    res.status(500).send(response);
}
};

答案 3 :(得分:0)

这是 JS 答案,不是 PHP,但无论如何

您可以使用此 URL 地址从 steamcommunity.com/search/ 获取用户列表 页

https://steamcommunity.com/search/SearchCommunityAjax?text=aaa&filter=users&sessionid=session&steamid_user=false&page=1

text 表示用户名,sessionid 表示 cookie 文件中的 sessionid,您可以通过访问站点本身获取

这是我糟糕的演示代码:

let axios = require('axios').default;

//create axios instance from which we will get to the search list
let instance = axios.create({ baseURL: 'https://steamcommunity.com' });

async function getSessionId() {

  let res = await axios.get('https://steamcommunity.com/');
  
  let [cookie] = res.headers['set-cookie'];
  
  instance.defaults.headers.Cookie = cookie;
  
  return cookie;

}

getSessionId().then(cookie => {

  let session = cookie.split(' ')[0].slice(10, -1);
  instance.get(`https://steamcommunity.com/search/SearchCommunityAjax?text=aaa&filter=users&sessionid=${session}&steamid_user=false&page=1`).then(res => {
  
    //i have regex
    let regex = /('<div>')/|/('<img>')/|/('<span>')/g
    
    //html also
    let arr = res.data.html.split(regex).join('').split('\t').join('').split('\n').join('').split('\r');

    arr = arr.filter(a => a !== '');
    
    arr = arr.filter(a => a.includes("searchPersonaName"));
    
    let result = [];

    arr.forEach(a => {
            
            let [link, name] = a.replace('<a class="searchPersonaName" href="','').replace('</a><br />','').split('">');

            let obj = {

                link,

                name

            };

            result.push(obj);
        
        });

        console.log(result); //logs out array of objects with links and usernames
  
  })
  
})

答案 4 :(得分:-6)

您是否从Steam Web API读过这篇文章?

https://developer.valvesoftware.com/wiki/Steam_Web_API#GetPlayerSummaries_.28v0002.29

它有一个使用steam profile url返回用户Steam ID的示例,还有一些其他参数来收集其他信息。

如果你从那里读了一下,它会说“返回任何Steam用户的朋友列表

示例网址:http://api.steampowered.com/ISteamUser/GetFriendList/v0001/?key=XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX&steamid=76561197960435530&relationship=friend

  • 您可以添加要返回的个人资料信息的参数,例如提供个人资料的Steam ID。