Question

在我的Spring MVC应用程序（Hibernate版本：4.1.7.final）中，我有一个包含long列表的实体，如下所示：

@Entity
@Table(name = "foo")
public class Foo {
    @Id
    private Long id;

    @ElementCollection
    @CollectionTable(
            name = "foo_numbers",
            joinColumns = {@JoinColumn(
                    name = "foo_id",
                    referencedColumnName = "id")})
    private Collection<Long> numbers;

    ...
}

目标是为那些列表为空或包含给定数字的Foos编写查询，如：

@Query("SELECT f FROM Foo AS f WHERE f.numbers IS EMPTY OR (:num) MEMBER OF f.numbers")
Collection<Foo> findTheRightFoos(@Param("num") Long num);

但我遇到了以下问题：

@Query("SELECT f FROM Foo AS f WHERE (:num) MEMBER OF f.numbers")
Collection<Foo> findFoos_1(@Param("num") Long num);
//org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '))' at line 1; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '))' at line 1
//Hibernate log: select fooba0_.id as id9_ from foo fooba0_ cross join foo_numbers numbers1_ where fooba0_.id=numbers1_.foo and (? in (.))

@Query("SELECT f FROM Foo AS f WHERE (:num) IN f.numbers")
Collection<Foo> findFoos_2(@Param("num") Long num);
//Can't start the app, got the following exception:
//antlr.NoViableAltException: unexpected end of subtree ...
//... Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected end of subtree [SELECT c FROM com.acme.Foo AS f WHERE (:num) IN f.numbers]

@Query("SELECT f FROM Foo AS f WHERE f.numbers = (:num)")
Collection<Foo> findFoos_3(@Param("num") Long num);
//org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [3870] did not match expected type [java.util.Collection]; nested exception is java.lang.IllegalArgumentException: Parameter value [3870] did not match expected type [java.util.Collection]

@Query("SELECT f FROM Foo AS f WHERE f.numbers IS EMPTY")
Collection<Foo> findFoos_4();
//Can't start the app, got the following exception:
//antlr.NoViableAltException: unexpected end of subtree ...
//... Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected end of subtree [SELECT c FROM com.acme.Foo AS f WHERE f.numbers IS EMPTY]

@Query("SELECT f FROM Foo AS f WHERE f.numbers IS NULL")
Collection<Foo> findFoos_5();
//org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'is null)' at line 1; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'is null)' at line 1
//Hibernate log: select fooba0_.id as id9_ from foo fooba0_ cross join foo_numbers numbers1_ where fooba0_.id=numbers1_.foo and (. is null)

@Query("SELECT f FROM Foo AS f WHERE f.numbers = NULL")
Collection<Foo> findFoos_6();
//org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'is null)' at line 1; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'is null)' at line 1
//Hibernate log same as 'findFoos_5': select fooba0_.id as id9_ from foo fooba0_ cross join foo_numbers numbers1_ where fooba0_.id=numbers1_.foo and (. is null)

这有什么问题？我怎么能这样做？

Answer 1

要实现所需的查询类型（在@ElementCollection的内容上），您需要更改为@OneToMany关联。这是我的支持（来自JPA: When to choose Multivalued Association vs. Element Collection Mapping）

使用@ElementCollection而不是@OneToMany的限制是无法独立于父对象查询，保留，合并目标对象。它们是严格的私有（依赖）对象，与@Embedded映射相同。 @ElementCollection上没有级联选项，目标对象始终保持，合并，与父级一起删除。 @ElementCollection仍然可以使用fetch类型，默认为LAZY，与其他集合映射相同。

Answer 2

正如guido所说，这是由于以下错误引起的：https://hibernate.atlassian.net/browse/HHH-6686

我已经尝试过了，现在肯定可以在5.4.11版中使用

JPQL查询 - 实体包含Longs列表

2 个答案: