在我的脚本文件中
for file in *.TXT
do
echo "put $file"
less $file | grep BPR | awk -F'CACH' {'print $1'}
done
我正在运行此命令减去XYZ.TXT | grep BPR | awk -F'CACH'{'print $ 1'},我就这样出来了。
BPRC000000000008801
BPRC000000000006671
BPRP000000000005088
BPRC000000000004542
BPRP000000000003805
BPRC000000000013624
BPRC000000000235668
从这些输出我需要计算每行的金额和总金额。
例如
BPRC000000000008801 88.01
BPRC000000000006671 66.71
BPRP000000000005088 50.88
BPRC000000000004542 45.42
BPRP000000000003805 38.05
BPRC000000000013624 136.24
BPRC000000000235668 2356.68
并且最终输出应该是总金额。我怎样才能做到这一点。请帮帮我。
答案 0 :(得分:1)
尝试使用两个sub()
函数。第一个删除所有字符直到非零数字。第二个添加小数点:
awk '
BEGIN { OFS = "\t" }
{ $2 = $1;
sub( /^[^0]*0*/, "", $2 );
sub( /..$/, ".\&", $2 );
print $0
}
' data
它产生:
BPRC000000000008801 88.01
BPRC000000000006671 66.71
BPRP000000000005088 50.88
BPRC000000000004542 45.42
BPRP000000000003805 38.05
BPRC000000000013624 136.24
BPRC000000000235668 2356.68
答案 1 :(得分:1)
请尝试以下操作:
awk -F'[A-Z]+' '{total += $2/100} END {printf "%.2f", total}' data
输入数据:
BPRC000000000008801
BPRC000000000006671
BPRP000000000005088
BPRC000000000004542
BPRP000000000003805
BPRC000000000013624
BPRC000000000235668
输出:
2781.99
如果你想在每一步都输出:
awk -F'[A-Z]+' '{printf "%s\t%.2f\n",$0, $2/100; total += $2/100} END {printf "Total = %.2f\n", total}' data
输出:
BPRC000000000008801 88.01
BPRC000000000006671 66.71
BPRP000000000005088 50.88
BPRC000000000004542 45.42
BPRP000000000003805 38.05
BPRC000000000013624 136.24
BPRC000000000235668 2356.68
Total = 2781.99
答案 2 :(得分:1)
而不是
awk -F'CACH' {'print $1'}
说
awk -F'CACH' '{c=$1;sub(/[^0-9]*/,"",c);}{print $1, c/100}'
编辑:为了获得总数,请说
awk -F'CACH' '{c=$1;sub(/[^0-9]*/,"",c);total+=c/100}{print $1, c/100}END{printf "%.2f", total}'