Question

我有1个选择下拉列表，我想根据选择下拉列表＃1的值创建另一个选择下拉列表。例如，我的下拉列表＃1的值为13-001,13-002,13-003，当我在13-001中选择时，它会在数据库中显示表中的记录，并且有一列po_number。我想要另一个选择下拉列表，其值为po_number取决于下拉列表＃1的值。

就像这样。下拉列表＃1 13，-001,13-002,13-003

下拉＃2当我选择13-001时，下拉列表＃2的值是111,222,333，基于从po_number列获取的值，并且仅显示下拉列表＃1 13-001和下拉列表＃2 111的记录。我只是在我的脚本中添加了一些id，但我不知道下一步是什么。

bid.php

<script>
        function showUser(str,ids) {
            var $txtHint = $('#txtHint');
            if (str=="" || ids=="") {
                $txtHint.html('');
                return;
            }
            $txtHint.load('bid_list.php?q='+str+'&id='+ids)
        }
        </script>
        </head>
        <body onload=showUser(str="ALL")>


        <?php
        $mysqli = new mysqli("localhost", "root", "", "app");
        $result = $mysqli->query("SELECT bid FROM procurement WHERE bid LIKE '13-___' OR bid LIKE '1_-___' OR bid LIKE '2_-___' GROUP BY bid ORDER BY bid");

        $option = '';
        while($row = $result->fetch_assoc())
        {
          $option .= '<option value = "'.$row['bid'].'">'.$row['bid'].'</option>';
        }
        ?>

        <div style="text-align:center;">
        <select name="users" onchange="showUser(this.value)" style="overflow:scroll;width:100px;">
                <option value="ALL" selected='ALL'>ALL</option>
                <?php echo $option; ?>
        </select>
        <?php
        $mysqli = new mysqli("localhost", "root", "", "app");
        $result = $mysqli->query("SELECT po_number FROM procurement WHERE po_number GROUP BY po_number ORDER BY po_number");

        $option1 = '';
        while($row = $result->fetch_assoc())
        {
          $option1 .= '<option value = "'.$row['po_number'].'">'.$row['po_number'].'</option>';
        }
        ?>
        <select style="overflow:scroll;width:100px;">
                <option value="ALL" selected='ALL'>ALL</option>
                <?php echo $option1; ?>
        </select>

        <div id="txtHint"></div>

bid_list.php

<?php
$mysqli = new mysqli("localhost", "root", "", "app");
$q = $_GET["q"];
$where = '';
if ( $q != 'ALL' ) {
    $where = " WHERE bid='$q' ";
}
$result1 = $mysqli->query("
    SELECT bid, item_name, item_description, unit, unit_cost, quantity, supplier, po_number, po_date, counter, SUM(unit_cost*quantity) AS total_amount 
    FROM procurement 
    $where 
    GROUP BY counter ORDER BY bid
");
echo'<table id="tfhover" cellspacing="0" class="tablesorter" style="text-transform:uppercase;">
        <thead>
        <tr>
            <th colspan="3" id="none" style="cursor: default;"></th>
            <th title="Item Name">Item Name</th>
            <th title="Item Description">Description</th>
            <th title="Example : Pc, Pcs, Box and Etc.">Unit</th>
            <th title="Item Price">Unit Cost</th>
            <th title="Total Item Quantity">QTY</th>
            <th title="Total Price">Total Amount</th>
            <th title="Name of Supplier">Supplier</th>
            <th title="Purchase Order #">PO #</th>
            <th title="Purchase Order Date">PO Date</th>
        </tr>
        </thead>';
        echo'<tbody>';
while($row = $result1->fetch_assoc()){
if($row['bid'] != '')
 {
 echo'<tr>
            <td align="center"><a href="'.$_SERVER['PHP_SELF'].'?de='.$row["counter"].'" onclick="return confirm(\'Really want to delete ?\');"><img src="images/del.png" border="0" width="10" height="10" title="Delete"></a></td>
            <td align="center"><a class="fancybox" href="edit.php?pn='.$row["counter"].'"><img src="images/edit.png" border="0" width="10" height="10" title="Edit"></a></td>
            <td align="center"><a class="fancybox" href="comments.php?pn='.$row["counter"].'"><img src="images/remarks.png" border="0" width="10" height="10" title="Remarks and Notes"></a></td>
            <td>'.$row['item_name'].'</td>
            <td>'.$row['item_description'].'</td>
            <td>'.$row['unit'].'</td>
            <td>'.number_format($row['unit_cost'], 2, '.', ',').'</td>
            <td>'.$row['quantity'].'</td>
            <td>'.number_format($row['total_amount'], 2, '.', ',').'</td>
            <td>'.$row['supplier'].'</td>
            <td>'.$row['po_number'].'</td>
            <td>'.$row['po_date'].'</td>
       </tr></tbody>';
       }
        }
    echo "</table>";

if (!$mysqli) {
    die('Connect Error: ' . mysqli_connect_error());
}
mysqli_close($mysqli);
    ?>

如何在另一个选择下拉列表中连接选择下拉列表以创建具有数据库值的组合框？

0 个答案: