我需要从Form1获取一个方法,但是当我调用它时,我得到一个无限循环错误。我得到这个是因为我在Form1的开头创建了一个新的GameManager类,我在GameManager中创建了一个新的Form1。如何从form1到GameManager获取方法而不会出现无限循环错误?
Form1中:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace CatAndMouse
{
public partial class Form1 : Form
{
GameManager myGM = new GameManager();
int dir = 0;
public Form1()
{
InitializeComponent();
newGame();
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if (this.myGM != null)
this.myGM.paint(e.Graphics);
//e.Graphics.DrawImage(imgMouse.Images[0], pointXMouse, pointYMouse);
//e.Graphics.DrawImage(imgCat.Images[0], 50, 100);
//e.Graphics.DrawImage(imgCheese.Images[0], 75, 100);
}
private void Form1_KeyDown(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.Up)
{
dir = 0;
}
if (e.KeyCode == Keys.Right)
{
dir = 1;
}
if (e.KeyCode == Keys.Down)
{
dir = 2;
}
if (e.KeyCode == Keys.Left)
{
dir = 3;
}
}
public void newGame()
{
timer1.Start();
myGM.newGame(imgCat, imgMouse, imgCheese);
}
private void timer1_Tick(object sender, EventArgs e)
{
pictureBox1.Refresh();
}
public int getDir()
{
return dir;
}
}
}
游戏管理:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace CatAndMouse
{
class GameManager
{
Form1 myForm = new Form1();
Cat ca1 = new Cat();
Mouse m = new Mouse();
Cheese ch = new Cheese();
int amount = 5;
int catdir = 0;
Timer time = new Timer();
public ImageList imgCat = new ImageList();
public ImageList imgMouse = new ImageList();
public ImageList imgCheese = new ImageList();
public void newGame(ImageList cat, ImageList mouse, ImageList cheese)
{
imgCat = cat;
imgMouse = mouse;
imgCheese = cheese;
time.Start();
}
public void move()
{
ca1.Move(amount);
m.Move(amount);
}
public void paint(Graphics g)
{
g.DrawImage(imgCat.Images[0], ca1.getLocation());
}
private void time_Tick(object sender, EventArgs e)
{
move();
getDir();
}
public void getDir()
{
catdir = myForm.getDir();
}
}
}
答案 0 :(得分:2)
将表单对象作为参数传递给GameManager对象。例如,在GameManager的构造函数中创建另一个争论' Form1形式'并做myForm = form;
从Form1调用构造函数时传递'这个'作为参数。
答案 1 :(得分:0)
如果您不想传递对整个表单的引用,您只能将委托传递给GameManager
构造函数。有关委托here
答案 2 :(得分:0)
将构造函数添加到GameManager
Form1 myForm;
public GameManager(Form1 form)
{
myForm = form;
}
然后Form1
GameManager myGM;
public Form1()
{
myGM = new GameManager(this);
}