我已经在Mac上编译了这段代码,所以我知道没有语法错误,但是,在VC ++ Express 2010中,我收到错误,说找不到fmin和fmax标识符。我安装了Windows SDK 7.1以查看是否能解决问题并且它什么也没做:/
#include "DigitalDistortion.h"
#include "IPlug_include_in_plug_src.h"
#include "IControl.h"
#include "resource.h"
const int kNumPrograms = 1;
enum EParams
{
kThreshold = 0,
kNumParams
};
enum ELayout
{
kWidth = GUI_WIDTH,
kHeight = GUI_HEIGHT,
kThresholdX = 100,
kThresholdY = 100,
kKnobFrames = 60
};
DigitalDistortion::DigitalDistortion(IPlugInstanceInfo instanceInfo)
: IPLUG_CTOR(kNumParams, kNumPrograms, instanceInfo), mThreshold(1.)
{
TRACE;
//arguments are: name, defaultVal, minVal, maxVal, step, label
GetParam(kThreshold)->InitDouble("Threshold", 100., 0.01, 100.0, 0.01, "%");
GetParam(kThreshold)->SetShape(2.);
IGraphics* pGraphics = MakeGraphics(this, kWidth, kHeight);
pGraphics->AttachPanelBackground(&COLOR_RED);
IBitmap knob = pGraphics->LoadIBitmap(KNOB_ID, KNOB_FN, kKnobFrames);
pGraphics->AttachControl(new IKnobMultiControl(this, kThresholdX, kThresholdY, kThreshold, &knob));
AttachGraphics(pGraphics);
//MakePreset("preset 1", ... );
MakeDefaultPreset((char *) "-", kNumPrograms);
}
DigitalDistortion::~DigitalDistortion() {}
void DigitalDistortion::ProcessDoubleReplacing(
double** inputs,
double** outputs,
int nFrames)
{
// Mutex is already locked for us.
int const channelCount = 2;
for (int i = 0; i < channelCount; i++) {
double* input = inputs[i];
double* output = outputs[i];
for (int s = 0; s < nFrames; ++s, ++input, ++output) {
if(*input >= 0) {
// Make sure positive values can't go above the threshold:
*output = fmin(*input, mThreshold);
} else {
// Make sure negative values can't go below the threshold:
*output = fmax(*input, -mThreshold);
}
*output /= mThreshold;
}
}
}
void DigitalDistortion::Reset()
{
TRACE;
IMutexLock lock(this);
}
void DigitalDistortion::OnParamChange(int paramIdx)
{
IMutexLock lock(this);
switch (paramIdx)
{
case kThreshold:
mThreshold = GetParam(kThreshold)->Value() / 100.;
break;
default:
break;
}
}
答案 0 :(得分:7)
fmin
和fmax
是C99功能。 Visual Studio仅实现C89标准,因此它没有这些功能。
答案 1 :(得分:3)
由于它是C ++,你可以(而且,我敢说,应该)使用std::min
标题中的std::max
和<algorithm>
函数。
这些是函数模板,因此它们将接受定义了比较运算符的任何类型。只需确保两个参数的类型相同,否则可能无法编译。