我正在尝试使用GSON解析JSON对象,如下所示:
{
"key1":"someValue",
"key2":{
"anotherKey1":"212586425",
"anotherKey2":"Martin"
}
}
这是代码:
Data data = new Gson().fromJson(json, Data.class);
以下是Data
类:
public class Data {
public String key1;
public Map key2; //This will break everything.
}
我期望(我是GSON的新手)是它将key2
的值作为Map
对象生成。
但是,我收到一个错误Expected BEGIN_OBJECT but was STRING
,这让我觉得我正在传递String
,我应该传递一个JSON对象。
不是GSON解析我在开始时传递的整个JSON字符串吗?所以最终,我希望新的数据源是Map
对象。这可行吗?
答案 0 :(得分:0)
让Gson做好工作。我将Data
定义为
package stackoverflow.questions.q19228349;
public class Data {
@Override
public String toString() {
return "Data [key1=" + key1 + ", key2=" + key2 + "]";
}
public String key1;
public Object key2;
}
然后我可以解析key2
的两种情况:
package stackoverflow.questions.q19228349;
import com.google.gson.Gson;
public class Q19228349 {
public static void main(String[] args){
String json =
"{\"key1\":\"someValue\","+
"\"key2\":{ "+
" \"anotherKey1\":\"212586425\","+
" \"anotherKey2\":\"Martin\""+
" }"+
" }";
String json2 =
"{\"key1\":\"someValue\","+
"\"key2\":\"aString\""+
" }";
Gson g = new Gson();
Data d = g.fromJson(json, Data.class);
System.out.println("First: " +d);
Data d2 = g.fromJson(json2, Data.class);
System.out.println("Second: "+d2);
}
}
结果如下:
首先:数据[key1 = someValue,key2 = {anotherKey1 = 212586425, anotherKey2 = Martin}]第二名:数据[key1 = someValue,key2 = aString]