Question

我希望获得用户朋友的列表，但是性别明智，在1个电话中。喜欢与用户或性别相同的朋友性别相同的朋友。目前，我必须拨2个电话。首先，获取用户的性别，然后获取第二个这样的列表

SELECT uid, name 
  FROM user 
 WHERE uid IN (
             SELECT uid2 
               FROM friend 
              WHERE uid1 =me()
              ) 
   AND sex='< gender >'

Answer 1

为了获得与您的性别相同的朋友：

获得性别：
select sex from user where uid = me()

结交所有朋友：
select uid, sex from user where uid in (select uid1 from friend where uid2 = me())

两者的结合：

select uid, sex from user where 
uid in 
(
    select uid1 from friend where uid2 = me()
) 
and 
sex in 
(
    select sex from user where uid = me()
)

修改

对于异性

select uid, sex from user where 
uid in 
(
    select uid1 from friend where uid2 = me()
) 
and not(sex in 
(
    select sex from user where uid = me()
))

这会在一个查询中向您回复与您相同/异性的所有朋友。

FQL - 获取相同或异性的朋友列表

1 个答案: