我有一个包含六列的jqGrid,每列都有一个'checkbox'格式。我需要根据列名称获取所有复选框的选定和未选定值。有可能吗?
第一列是提供一个选择所有剩余列的选项。
在定义onclick
时,我无法添加onselect
或colModel
等事件监听器。
$("#Grid").jqGrid({
url: '@Url.Action("Access", "Authorization")' + '?role=' + encodeURIComponent($('input#hIDRole').val()),
datatype: 'json',
colNames: ["IDAccess","Permission", "ALL", "Read", "Add", "Edit", "Copy", "Delete"],
colModel: [
{ name: 'IDAccess', index: 'IDAccess', width: 10, resizable: false, editable: false, hidden: true },
{ name: 'Permission', index: 'Permission', width: 100, resizable: false, editable: false, hidden: false },
{ name: 'ALL', index: 'ALL', editable: true, edittype: 'checkbox', editoptions: { value: "True:False" }, formatter: "checkbox", width: 50, resizable: false, formatoptions: { disabled: false }, onselect: "checkBox(this.value())" },
{ name: 'IsRead_Allowed', index: 'IsRead_Allowed', editable: true, edittype: 'checkbox', formatter: "checkbox", editoptions: { value: "True:False" }, width: 50, resizable: false, formatoptions: { disabled: false }, onclick: "checkBox(checked,this.value)" },
{ name: 'IsCreate_Allowed', index: 'IsCreate_Allowed', editable: true, edittype: 'checkbox', editoptions: { value: "True:False" }, formatter: "checkbox", width: 50, resizable: false, editable: true, formatoptions: { disabled: false }, onclick:"checkBox(event)" },
{ name: 'IsUpdateAllowed', index: 'IsUpdateAllowed', editable: true, edittype: 'checkbox', editoptions: { value: "True:False" }, formatter: "checkbox", width: 50, resizable: false, editable: true, formatoptions: { disabled: false }, },
{ name: 'IsCopy_Allowed', index: 'IsCopy_Allowed', editable: true, edittype: 'checkbox', editoptions: { value: "True:False" }, formatter: "checkbox", width: 50, resizable: false, editable: true, formatoptions: { disabled: false } },
{ name: 'IsDeleteAllowed', index: 'IsDeleteAllowed', editable: true, edittype: 'checkbox', editoptions: { value: "True:False" }, formatter: "checkbox", width: 50, resizable: false, editable: true, formatoptions: { disabled: false } },
],
//rowNum: 10,
//rowList: [10],
pager: "#pager-json",
autowidth: true,
loadComplete: function () {
var rowIDs = $("#Grid").jqGrid('getDataIDs');
for (var i = 0; i < rowIDs.length ; i++) {
var rowId = rowIDs[i];
var rowData = jQuery('#Grid').jqGrid('getRowData', rowId);
//below code to check the All column if the other columns have true in the db. But once checked attribute is added i am not able to uncheck
if ((rowData['IsRead_Allowed'] == "True") && (rowData['IsCreate_Allowed'] == "True") && (rowData['IsUpdateAllowed'] == "True")
&& (rowData['IsCopy_Allowed'] == "True") && (rowData['IsDeleteAllowed'] == "True")) {
var check = $("#" + rowId).find('input[type="checkbox"]');
check.attr('checked', 'checked');
}
}
for (var i = 0; i < rowIDs.length; i++) {
var rowData = rowIDs[i];
if (rowData['IsCopy_Allowed'] == null) {
//alert("1");
var checkbox = $("#Grid" + rowData.i);
//checkbox.css("visibility", "hidden");
checkbox.attr("disabled", true);
}
}
}
});
答案 0 :(得分:0)
您可以使用以下选择器获取所有输入元素:
jQuery(".jqgrow td input", "#my_grid").each(function(){
jQuery(this).unbind('click');
jQuery(this).click(function(){
...
});
});
input
元素实际上将包含在td
:
<td ... aria-describedby="my-column"><input type="checkbox" ...></td>
您可以使用aria-describedby
元素上的td
来确定是否添加点击处理程序。类似的东西:
var col = jQuery(this).parent().attr('aria-describedby');
if (col === "IDAccess") {
// Add handler here, etc...
}
您需要通过类似的练习来查找特定行中的所有复选框,但使用ID可能会限制搜索,即:
jQuery(".jqgrow td input", "#" + my_id)
或者,您也可以使用classes
colmodel选项为每列分配一个唯一的类。例如:classes:'col1'
。这将简化您的代码以设置点击处理程序,并可能允许您完全避免使用aria
属性。