我正在将一个SBT插件从0.12
移到0.13
。在我的插件的各个点上,我将一组动态任务安排到SBT构建图上。
以下是我的旧代码。这仍然是表达这一点的惯用方式,还是可以利用宏来使一切变得更漂亮?
import sbt._
import Keys._
object Toplevel extends Build
{
lazy val ordinals = taskKey[Seq[String]]("A list of things")
lazy val times = taskKey[Int]("Number of times to list things")
lazy val inParallel = taskKey[Seq[String]]("Strings to log in parallel")
lazy val Foo = Project( id="Foo", base=file("foo"),
settings = Defaults.defaultSettings ++ Seq(
scalaVersion := "2.10.2",
ordinals := Seq( "First", "Second", "Third", "Four", "Five" ),
times := 3,
inParallel <<= (times, ordinals, streams) flatMap
{ case (t, os, s) =>
os.map( o => toTask( () =>
{
(0 until t).map( _ => o ).mkString(",")
} ) ).join
}
)
)
}
为完全做作的例子道歉!
修改
因此,考虑到Mark的建议,我有以下更整洁的代码:
import sbt._
import Keys._
object Toplevel extends Build
{
lazy val ordinals = taskKey[Seq[String]]("A list of things")
lazy val times = taskKey[Int]("Number of times to list things")
lazy val inParallel = taskKey[Seq[String]]("Strings to log in parallel")
def parTask = Def.taskDyn
{
val t = times.value
ordinals.value.map(o => ordinalTask(o, t)).join
}
def ordinalTask(o: String, t: Int) = Def.task
{
(0 until t).map(_ => o).mkString(",")
}
lazy val Foo = Project( id="Foo", base=file("foo"),
settings = Defaults.defaultSettings ++ Seq(
scalaVersion := "2.10.2",
ordinals := Seq( "First", "Second", "Third", "Four", "Five" ),
times := 3,
inParallel := parTask.value
)
)
}
这似乎几乎就在那里,但是在构建时失败了:
[error] /home/alex.wilson/tmp/sbt0.13/project/build.scala:13: type mismatch;
[error] found : sbt.Def.Initialize[Seq[sbt.Task[String]]]
[error] required: sbt.Def.Initialize[sbt.Task[?]]
[error] ordinals.value.map(o => ordinalTask(o, t)).join
答案 0 :(得分:3)
您可以使用Def.taskDyn
,它为flatMap
提供新语法。与Def.task
的区别在于,预期的返回类型是一个任务Initialize[Task[T]]
,而不仅仅是T
。翻译你的例子,
inParallel := parTask.value
def parTask = Def.taskDyn {
val t = times.value
ordinals.value.map(o => ordinalTask(o, t)).joinWith(_.join)
}
def ordinalTask(o: String, t: Int) = Def.task {
(0 until t).map(_ => o).mkString(",")
}