Question

在我一直在研究的项目中，我们必须将C ++子项目中的Cocoa通知发送到它上面的主项目。为此，我们构造一个映射，作为通知的userInfo字典的键值存储。

在其中一个项目中，以下代码编译得很好：

std::map<std::string, std::string> *userInfo = new std::map<std::string, std::string>;
char buffer[255];

sprintf(buffer, "%i", intValue1);
userInfo->insert(std::pair<std::string, std::string>("intValue1", std::string(buffer)));

sprintf(buffer, "%i", intValue2);
userInfo->insert(std::pair<std::string, std::string>("intValue2", std::string(buffer)));

if(condition)
    userInfo->insert(std::pair<std::string, std::string>("conditionalValue", "true"));

PostCocoaNotification("notificationName", *userInfo);

但是，当将其复制到另一个子项目中的相同文件中时，编译器会在userInfo-＆gt;插入调用上抛出以下内容：

"Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'"

..它无法找到PostCocoaNotification的函数：

No matching function for call to 'PostCocoaNotification'

此外，它会在系统标头中引发以下错误：

/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:73:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:74:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:73:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_tree.h:1324:13: Cannot initialize a parameter of type '_Link_type' (aka '_Rb_tree_node<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > *') with an rvalue of type '_Const_Link_type' (aka 'const _Rb_tree_node<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > *')

我不知道我做了什么导致这样的混乱，特别是当代码在另一个子项目中运行完全正常（成功发送通知）时。对此问题的任何见解都将非常受欢迎。

Answer 1

您需要包含以下标题：

#include <string>
#include <sstream>
#include <iostream>

未定义模板'std :: basic_string <char，std :: char_traits <char =“”>，std :: allocator <char>＆gt;'</char> </char，>的隐式实例化

1 个答案: