Question

我有问题。我的字符串格式为"abc"，它有“”。现在我想从abc获得"abc"（意味着从字符串中删除“”并仅获取abc）。我怎样才能做到这一点？提前致谢

Answer 1

NSString *abc = [@"\"abc\"" stringByReplacingOccurencesOfString:@"\"" withString:@""];

Answer 2

#import <Foundation/Foundation.h>

int main(int argc, const char **argv) {
    @autoreleasepool {
        NSString *input = @"\"abc\"";
        NSArray *elements = [input componentsSeparatedByString:@"\""];
        if ([elements count] > 0) {
            NSString *element = [elements objectAtIndex:1];
            NSLog(@"count=%lu element='%@'", [elements count], element);
        }
    }
    return 0;
}

$ clang -o strsep strsep.m -framework Foundation
$ ./strsep
2013-10-07 11:42:44.274 strsep[34292:707] count=3 element='abc'

Answer 3

[String replaceOccurrencesOfString:@"\"" withString:@"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [String length])];

Answer 4

有一个内置函数，可以让你用另一个子串替换所有出现的子串 - 如果另一个子串被设置为空字符串（ @“”），它将有效删除所有出现的子串。你的例子：

NSString * yourNewString = [yourOldString stringByReplacingOccurrencesOfString:@"\"" withString:@""]);

Answer 5

您可以使用空格替换“空格。”

NSString *some = @"\"abc\"";
NSLog(@"%@",some);
NSString *newString = [some stringByReplacingOccurrencesOfString:@"\"" withString:@""];
NSLog(@"%@",newString);

Answer 6

我为你写了一个方法，这将完美地运作:(如果你的最后一个字符是“）

- (NSString*) getTheString:(NSString*) yourString{
    NSString* answerString = [[NSString alloc]init];

    int substrinFrom = 0;
    for (NSInteger charIdx=0; charIdx<[yourString length]; charIdx++){

        if ( '"' == [yourString characterAtIndex:charIdx]) {
            substrinFrom = charIdx;
            NSLog(@"%i",substrinFrom);
            break;
        }
    }
    answerString = [yourString substringWithRange:NSMakeRange(substrinFrom+1, [yourString length] - substrinFrom -2 )];

    return answerString;

}

测试它：

NSString* test = [self getTheString:@"\"Hello this is a test string, and it will work\""];
NSLog(@"%@",test);

如何从字符串中剪切字符串＆＃34; abc＆＃34;在iOS中

6 个答案: