Question

我想要做的是从我的数据库中选择VID = 1和最大VID = 25000的视频，我有400k视频，但我不想启动它们所以我需要选择这种方式，我为搜索脚本制作此命令，但我怎么看它不起作用...希望有人可以帮我解决这个问题

用于搜索的MySql命令（此命令用于显示找到的视频数量）：

  select 
  count(*) as num 
  from 
    video 
 where 
    VID BETWEEN 1 AND 25000 
 AND 
    title LIKE '%key1%' 
 or 
    title LIKE '%key2%' 
 or 
    title LIKE '%key3%' 
 or 
    title LIKE '%key4%'

Answer 1

我认为您需要通过在AND子句

中添加括号来使用运算符优先级

   select 
    count(*) as num 
    from 
        video 
    where 
        VID BETWEEN 1 AND 25000 
    AND 
        (title LIKE '%key1%' 
    or 
        title LIKE '%key2%' 
    or 
        title LIKE '%key3%' 
    or 
        title LIKE '%key4%' );

Answer 2

在括号（）中添加LIKE，尝试执行以下操作：

select count(some_id) as num from video where 
VID >= 1 AND VID <= 25000 AND 
(title LIKE '%key1%' or title LIKE '%key2%' or title LIKE '%key3%' or title LIKE '%key4%')

Answer 3

尝试以下：

select count(*) as num from video where VID BETWEEN 1 AND 25000 AND (title LIKE '%key1%' or title LIKE '%key2%' or title LIKE '%key3%' or title LIKE '%key4%')

Answer 4

只需在括号中设置所有标题比较。

select 
  count(*) as num 
  from 
    video 
 where 
    VID BETWEEN 1 AND 25000 
 AND (
    title LIKE '%key1%' 
 or 
    title LIKE '%key2%' 
 or 
    title LIKE '%key3%' 
 or 
    title LIKE '%key4%' 
)

Answer 5

试试这个

 SELECT count(title) as num 
 FROM video 
 WHERE vid <= 25000 
 AND (title LIKE '%key1%' OR title LIKE '%key2%' OR title LIKE '%key3%' OR title LIKE '%key4%')

Answer 6

你的介绍很好，真正的问题是你的当前脚本是这样执行的，因为AND运算符的优先级高于OR：

select 
count(*) as num 
from 
  video 
where 
  (VID BETWEEN 1 AND 25000 
AND 
  title LIKE '%key1%')
or 
  title LIKE '%key2%' 
or 
  title LIKE '%key3%' 
or 
  title LIKE '%key4%'

所以你需要做的是改变它：

select 
count(*) as num 
from 
  video 
where 
  VID BETWEEN 1 AND 25000 
AND (
  title LIKE '%key1%'
or 
  title LIKE '%key2%' 
or 
  title LIKE '%key3%' 
or 
  title LIKE '%key4%' )

Answer 7

试试这个

select 
    count(if(vid between 1 and 25000, 1, 0)) as totalvideocnt
from
    video
where
    (title like '%key1%' or title like '%key2%' or title like '%key3%' or title like '%key4%')

Mysql命令从id到id进行选择以进行搜索

7 个答案: