Android - 将资产复制到内部存储

时间：2013-10-07 07:01:47

标签： java android

美好的一天！

我刚开始为android开发。在我的应用中，我需要将资产文件夹中的项目复制到内部存储区。

我在SO上搜索了很多，包括将其复制到外部存储器。 How to copy files from 'assets' folder to sdcard?

这是我想要实现的目标： 我有一个目录已经存在于内部存储器中作为X＆gt; Y＆gt; Z.我需要一个文件复制到Y，另一个文件复制到Z。

任何人都可以帮我解决代码段吗？我真的不知道如何继续这个。

抱歉我的英语不好。

非常感谢。

8 个答案:

答案 0 :(得分：19)

使用

 String out= Environment.getExternalStorageDirectory().getAbsolutePath() + "/X/Y/Z/" ; 

        File outFile = new File(out, Filename);

在您的参考编辑后。链接答案。 

private void copyAssets() {
    AssetManager assetManager = getAssets();
    String[] files = null;
try {
    files = assetManager.list("");
} catch (IOException e) {
    Log.e("tag", "Failed to get asset file list.", e);
  }
 for(String filename : files) {
    InputStream in = null;
    OutputStream out = null;
    try {
      in = assetManager.open(filename);

      String outDir = Environment.getExternalStorageDirectory().getAbsolutePath() + "/X/Y/Z/" ; 

      File outFile = new File(outDir, filename);

      out = new FileOutputStream(outFile);
      copyFile(in, out);
      in.close();
      in = null;
      out.flush();
      out.close();
        out = null;
      } catch(IOException e) {
          Log.e("tag", "Failed to copy asset file: " + filename, e);
         }       
       }
     }
     private void copyFile(InputStream in, OutputStream out) throws IOException {
        byte[] buffer = new byte[1024];
      int read;
     while((read = in.read(buffer)) != -1){
       out.write(buffer, 0, read);
     }
   }

答案 1 :(得分：9)

嗨，大家好我做过这样的事。 允许您复制从Android AssetManager复制的所有目录结构：）

public String copyDirorfileFromAssetManager(String arg_assetDir, String arg_destinationDir) throws IOException
{
    File sd_path = Environment.getExternalStorageDirectory(); 
    String dest_dir_path = sd_path + addLeadingSlash(arg_destinationDir);
    File dest_dir = new File(dest_dir_path);

    createDir(dest_dir);

    AssetManager asset_manager = getApplicationContext().getAssets();
    String[] files = asset_manager.list(arg_assetDir);

    for (int i = 0; i < files.length; i++)
    {

        String abs_asset_file_path = addTrailingSlash(arg_assetDir) + files[i];
        String sub_files[] = asset_manager.list(abs_asset_file_path);

        if (sub_files.length == 0)
        {
            // It is a file
            String dest_file_path = addTrailingSlash(dest_dir_path) + files[i];
            copyAssetFile(abs_asset_file_path, dest_file_path);
        } else
        {
            // It is a sub directory
            copyDirorfileFromAssetManager(abs_asset_file_path, addTrailingSlash(arg_destinationDir) + files[i]);
        }
    }

    return dest_dir_path;
}


public void copyAssetFile(String assetFilePath, String destinationFilePath) throws IOException
{
    InputStream in = getApplicationContext().getAssets().open(assetFilePath);
    OutputStream out = new FileOutputStream(destinationFilePath);

    byte[] buf = new byte[1024];
    int len;
    while ((len = in.read(buf)) > 0)
        out.write(buf, 0, len);
    in.close();
    out.close();
}

public String addTrailingSlash(String path)
{
    if (path.charAt(path.length() - 1) != '/')
    {
        path += "/";
    }
    return path;
}

public String addLeadingSlash(String path)
{
    if (path.charAt(0) != '/')
    {
        path = "/" + path;
    }
    return path;
}

public void createDir(File dir) throws IOException
{
    if (dir.exists())
    {
        if (!dir.isDirectory())
        {
            throw new IOException("Can't create directory, a file is in the way");
        }
    } else
    {
        dir.mkdirs();
        if (!dir.isDirectory())
        {
            throw new IOException("Unable to create directory");
        }
    }
}

答案 2 :(得分：6)

尝试以下代码

private void copyAssets() {
    AssetManager assetManager = getAssets();
    String[] files = null;
    try {
        files = assetManager.list("");
    } catch (IOException e) {
        Log.e("tag", "Failed to get asset file list.", e);
    }
    for(String filename : files) {
        InputStream in = null;
        OutputStream out = null;
        try {
          in = assetManager.open(filename);
          File outFile = new File(getExternalFilesDir(null), filename);
          out = new FileOutputStream(outFile);
          copyFile(in, out);
          in.close();
          in = null;
          out.flush();
          out.close();
          out = null;
        } catch(IOException e) {
            Log.e("tag", "Failed to copy asset file: " + filename, e);
        }       
    }
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
    byte[] buffer = new byte[1024];
    int read;
    while((read = in.read(buffer)) != -1){
      out.write(buffer, 0, read);
    }
}

答案 3 :(得分：3)

我对Kotlin的小解决方案，从资产到内部存储的复制数据

try{...} cath{...}

答案 4 :(得分：2)

这是我的 Kotlin 解决方案，带有可自动关闭的流以复制到内部应用存储中：

val copiedFile = File(context.filesDir, "copied_file.txt")
context.assets.open("original_file.txt").use { input ->
    copiedFile.outputStream().use { output ->
        input.copyTo(output, 1024)
    }
}

答案 5 :(得分：1)

public void addFilesToSystem(String sysName, String intFil, Context c){
             //sysName is the name of the file we have in the android os
             //intFil is the name of the internal file



             file = new File(path, sysName + ".txt");

             if(!file.exists()){
                 path.mkdirs();

                 try {

                     AssetManager am = c.getAssets();

                     InputStream is = am.open(intFil);
                     OutputStream os = new FileOutputStream(file);
                     byte[] data = new byte[is.available()];
                     is.read(data);
                     os.write(data);
                     is.close();
                     os.close();

                     Toast t = Toast.makeText(c, "Making file: " + file.getName() + ". One time action", Toast.LENGTH_LONG);
                     t.show();

                     //Update files for the user to use
                     MediaScannerConnection.scanFile(c,
                             new String[] {file.toString()},
                             null, 
                             new MediaScannerConnection.OnScanCompletedListener() {

                         public void onScanCompleted(String path, Uri uri) {
                             // TODO Auto-generated method stub

                         }
                     });



                 }  catch (IOException e) {
                     Toast t = Toast.makeText(c, "Error: " + e.toString() + ". One time action", Toast.LENGTH_LONG);
                     t.show();
                     e.printStackTrace();
                 }

             }
         }

要添加文件，请调用addFilesToSystem（＆＃34; this_file_is_in_the_public_system＆＃34;，＆＃34; this_file_is_in_the_assets_folder＆＃34;，context / 如果您没有活动中的方法，则此上下文 /

希望有所帮助

答案 6 :(得分：0)

您可以使用Envrionment#getDataDirectory方法。它将给出内部存储器的数据目录的路径。这通常是存储所有应用相关数据的地方。

或者，如果要存储在根目录中，可以使用Environment#getRootDirectory方法。

答案 7 :(得分：0)

如果您需要将任何文件从资产复制到内部存储器，并且仅执行一次：

public void writeFileToStorage() {
        Logger.d(TAG, ">> writeFileToStorage");

        AssetManager assetManager = mContext.getAssets();
        if (new File(getFilePath()).exists()) {
            Logger.d(TAG, "File exists, do nothing");
            Logger.d(TAG, "<< writeFileToStorage");
            return;
        }

        try (InputStream input = assetManager.open(FILE_NAME);
             OutputStream output = new FileOutputStream(getFilePath())) {

            Logger.d(TAG, "File does not exist, write it");

            byte[] buffer = new byte[input.available()];
            int length;
            while ((length = input.read(buffer)) != -1) {
                output.write(buffer, 0, length);
            }

        } catch (FileNotFoundException e) {
            e.printStackTrace();
            Logger.e(TAG, "File is not found");
        } catch (IOException e) {
            e.printStackTrace();
            Logger.d(TAG, "Error while writing the file");
        }

        Logger.d(TAG, "<< writeFileToStorage");
    }

public String getFilePath() {
    String filePath = mContext.getFilesDir() + "/" + FILE_NAME;
    Logger.d(TAG, "File path: " + filePath);
    return filePath;
}
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