Question

说我有以下单词我想列入一个列表

"cat,dog,fish"         (first row)
"turtle,charzard,pikachu,lame"    (second row)
"232.34,23.4,242.12%"           (third row)

我的问题是我如何计算每一行中的标记，如第一行有3，第二行有4，第三行有3.之后如何计算字符数，然后为每一行决定哪个标记有大多数人物？所以输出看起来像

token count = 3, character count = 10, fish has the most characters
token count = 4, character count = 25, charzard has the most characters
token count = 3, character count = 17, 242.12% has the most characters

仅使用像len（）这样的简单列表方法。并使用逗号作为分隔符。谢谢，我真的输了，因为每次我尝试使用strip（'，'）删除逗号我都会收到错误

Answer 1

试试这个。适用于Python2和Python3

rows = [ "cat,dog,fish", "turtle,charzard,pikachu,lame", "232.34,23.4,242.12%" ]
for row in rows:
    tokens = row.split(',')
    token_cnt = len(tokens)
    char_cnt = sum([len(token) for token in tokens])
    longest_token = max(tokens, key=len)
    print("token count = %d, character count = %d, %s has the most characters" %(token_cnt, char_cnt, longest_token))

结果：

>>> token count = 3, character count = 10, fish has the most characters
>>> token count = 4, character count = 25, charzard has the most characters
>>> token count = 3, character count = 17, 242.12% has the most characters

<强>编辑：

现在使用max而非我愚蠢的sort选择来找到最长的单词，受@ inspectorG4dget的回答启发。

Answer 2

给出一个字符串列表：

def my_output(string_of_tokens):
    tokens = string_of_tokens.split(",")
    print "token count = %s, character count = %s, %s has the most characters" %
        (len(tokens), sum(map(len, tokens)), reduce(lambda a, b: a if len(a) > len(b) else b, tokens))

list = ["cat,dog,fish", "turtle,charzard,pikachu,lame", "232.34,23.4,242.12%"]
for l in list:
    my_output(l)

Answer 3

假设您有一个逗号分隔的行文件：

with open('path/to/input') as infile:
  for i,line in enumerate(infile, 1):
    toks = line.split(',')
    print "row %d: token_count=%d character_count=%d '%s' has the most characters" %(len(toks), sum(len(t) for t in toks), max(toks, key=len))

Answer 4

计算每行令牌的数量

试试这个

import re
print len(re.findall(r'\w+', line))

<强> DEMO

计算列表中的标记和字符

4 个答案: