Question

我有几个servlet，

将JSON编码的请求作为输入，
处理它们和
将对客户端的响应作为JSON编码对象返回。

到目前为止，我使用Android作为客户端（示例Android代码见下文）。

现在我想编写一个普通的旧Java程序，它将发送请求并接收响应（与Android代码相同）。为此，我编写了一个Java测试（代码见下文， Java代码部分）并运行它。

在客户端，我收到此错误：

21:43:38.930 [main] ERROR r.a.c.t.TestAcceptanceProcedure1 - 
java.io.IOException: Server returned HTTP response code: 405 for URL: http://myserver/myapp/rest/GetUserIdService
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1441) ~[na:1.6.0_23]
    at testclient.TestAcceptanceProcedure1.test(TestAcceptanceProcedure1.java:47) ~[test-classes/:na]

在服务器日志中，我看到以下消息：

WARNING: No operation matching request path "/myapp/rest/GetUserIdService" is found, Relative Path: /, HTTP Method: GET, ContentType: */*, Accept: text/html,image/gif,image/jpeg,*/*,*/*;q=.2,. Please enable FINE/TRACE log level for more details

问题：我应该如何更改Java测试以修复此错误？

请注意，服务器已启动并正在运行（当我执行Android代码时，它可以正常运行）。

Android代码：

发送请求并收到回复：

final GetSimulationStatusRequest request = new GetSimulationStatusRequest();
final String json = Utils.convertToJson(request, getClass());
final String serverUrl = Utils.getServerUrl(this, "GetSimulationStatusService");

final IGetSimulationStatusAsyncTask getSimulationStatusTask = 
        asyncTaskFactory.createGetSimulationStatusAsyncTask(getWebServiceHelper());

Utils.setRequestAndServerUrl(json, serverUrl, getSimulationStatusTask);

final GetSimulationStatusResponse simulationStatusReponse = 
        getSimulationStatusTask.get();

Utils.convertToJson：

public static String convertToJson(final Object aRequest, Class<? extends Activity> aClass) {
    final ObjectMapper mapper = new ObjectMapper();
    String json = null;

    try {
        json = mapper.writeValueAsString(aRequest);
    } catch (final JsonProcessingException exception) {
        Log.e(aClass.getSimpleName(), exception.getLocalizedMessage(),
                exception);
    }
    return json;
}

Utils.setRequestAndServerUrl：

public static void setRequestAndServerUrl(final String aJson,
        final String aServerUrl, final IAsyncTask aTask) {
    aTask.addNameValuePair("request", aJson);
    aTask.sendRequest(new String[] { aServerUrl });
}

GetSimulationStatusAsyncTask：

public class GetSimulationStatusAsyncTask 
    extends AsyncTask<String, String, GetSimulationStatusResponse> 
    implements IGetSimulationStatusAsyncTask {
    private static final String TAG = GetSimulationStatusAsyncTask.class.getSimpleName();
    private IWebServiceTaskHelper helper;
    private ICcpResponseParser<GetSimulationStatusResponse> responseParser = 
            new CcpResponseParser<GetSimulationStatusResponse>();


    public GetSimulationStatusAsyncTask(final IWebServiceTaskHelper aHelper) {
        helper = aHelper;
    }

    @Override
    public void addNameValuePair(final String aName, final String aValue) {
        helper.addNameValuePair(aName, aValue);
    }

    @Override
    protected GetSimulationStatusResponse doInBackground(String... aArgs) {
        return (GetSimulationStatusResponse)Utils.processResponse(this.helper, TAG, responseParser, 
                GetSimulationStatusResponse.class, aArgs);
    }

    @Override
    public void sendRequest(final String[] aArgs) {
        execute(aArgs);
    }
}

Java代码：

@Test
public void test() throws JsonProcessingException, MalformedURLException {
    final GetUserIdRequest request = new GetUserIdRequest();

    request.setDeviceId("PC1");

    final String requestAsString = convertToJson(request);
    final String serverUrl = getServerUrl("GetUserIdService");

    final URL url = new URL(serverUrl);
    HttpURLConnection connection = null;
    InputStream inputStream = null;
    try {

        connection = (HttpURLConnection) url.openConnection();
        connection.addRequestProperty("request", requestAsString);
        connection.connect();

        inputStream = connection.getInputStream();
        final String responseAsString = IOUtils.toString(inputStream);

        LOGGER.debug("responseAsString: " + responseAsString);

    } catch (final IOException exception) {
        LOGGER.error("", exception);
    }
    finally
    {
        IOUtils.closeQuietly(inputStream);
    }
}

private String convertToJson(final GetUserIdRequest aRequest) throws JsonProcessingException {
    final ObjectMapper mapper = new ObjectMapper();
    return mapper.writeValueAsString(aRequest);
}

private String getServerUrl(final String aServiceName)
{
    return "http://myserver.com/myapp/rest/" + aServiceName;
}

更新1（09.10.2013 12:23 MSK）：

@Path("/GetSimulationStatusService")
public class GetSimulationStatusService extends BaseCcpService  {
  private GetSimulationStatusRequestParser requestParser = 
      new GetSimulationStatusRequestParser();

  @POST
  @Produces("text/plain")
  public String getSimulationStatus(@FormParam("request") final String aRequestJson) 
      throws JsonProcessingException
  {
    final GetSimulationStatusRequest request = requestParser.convert(aRequestJson);

    final GetSimulationStatusResponse response = new GetSimulationStatusResponse();

    response.setRequestId(request.getId());
    response.setCycle(getPersistence().getCurrentCycle(request.getUserId()));
    response.setLabourForce(getPersistence().getLabourForceSimulationParameter(
        request.getUserId()));

    return getObjectMapper().writeValueAsString(response);
  }
}

更新2（09.10.2013 20:48 MSK）：当我更改如下所示的代码时，我得到500个HTTP响应。在服务器端，方法aRequest的{{1}}参数为空。

GetUserIdService.getUserId

更新3（09.10.2013 23:15）：这个有效：

        connection = (HttpURLConnection) url.openConnection();
        connection.addRequestProperty("request", requestAsString);
        connection.setRequestMethod("POST"); // Added this line
        connection.connect();

Answer 1

405 HTTP错误代码表示端点不支持给定方法（GET）。可能代替GET请求你想发送POST。我不知道Android客户端发送了什么样的请求。

您是否有端点规范/文档？

Here您将找到有关如何使用普通Java API调用POST的信息。如果您可以在测试中使用外部库，那么使用RESTEasy可以更轻松地实现它。

如何向基于Apache CXF的服务发送请求和接收响应？

1 个答案: