Question

我有查看单元格的tableview，每个单元格都会推送detailViewController。我想在detailViewController中将单元格的文本分配给textLabel。

.h类的masterView

@property (strong,nonatomic) NSString *selectedCellText;

.m类的masterView

@synthesize selectedCellText = _selectedCellText;

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    self.selectedCellText = [[[tableView cellForRowAtIndexPath:indexPath] textLabel] text];
    NSLog(@"%@",self.selectedCellText);
}

这里NSLog打印单元格的名称

.h of detailViewController

@property (nonatomic, copy) listOfTricksViewController *aReference;

.m of detailViewController

@synthesize aReference = _aReference;

- (void)viewDidLoad
{

    [super viewDidLoad];
    self.detailViewName.text = self.aReference.selectedCellText;
     NSLog(@"%@",self.aReference.selectedCellText);
}

NSLog打印null。

Answer 1

像这样修改方法prepareForSegue：

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{ 
    if([[segue identifier] isEqualToString:@"detailTrick"])
    { 
        DetailViewController *detailViewController = (DetailViewController *)segue.
        NSString *object = nil; 
        NSIndexPath *indexPath = nil;
        indexPath = [self.tableView indexPathForSelectedRow]; 

        // Pass data
        detailViewController.aString = self.cellObjects[indexPath.row]; 
    } 
}

您需要致电DetailViewController并将数据转发给此控制器（假设此处@property标题中有DetailViewController aString

.h of detailViewController

@property (nonatomic, strong) NSString *aString;

.m of detailViewController

- (void)viewWillAppear:(BOOL)animated
{

    [super viewWillAppear:animated];

    self.detailViewName.text = self.aString;
     NSLog(@"%@",self.aString);
}

从另一个类的属性访问文本

1 个答案: