Question

我可以通过NSObject将数据从表传递到其他表吗？

示例：

第一张表发送数据

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
     NSIndexPath *path = [self.tableView indexPathForSelectedRow];
     Data *g = [[Data alloc]init];
     [g setSelection1:(int)path.row];
}

NSLog test selecttion1 value = path.row;

当我使用第二个表时，我导入数据并分配它，但我在selection1中的值丢失了。

总是0;

Answer 1

您的Data对象不会为您提供服务，因为您尚未将其传递给目标视图控制器。

你可以这样做

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
     NSIndexPath *path = [self.tableView indexPathForSelectedRow];
     Data *g = [[Data alloc]init];
     [g setSelection1:(int)path.row];

     MyTargetViewController *targetVC = segue.destinationViewController;
     [targetVC setData:g];
}

这里将“MyTargetViewController”替换为您的实际目标视图控制器。

Answer 2

试试这个：

-(void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender 
{
    if ([segue.identifier isEqualToString:@"<YOUR_SEQUE_IDENTIFIER_GOES_HERE>"]) 
    {
        <YOUR_CONTROLLER> *destController =  (<YOUR_CONTROLLER> *)  
                                              segue.destinationViewController;

         NSIndexPath *path = [self.tableView indexPathForSelectedRow];
         Data *g = [[Data alloc] init]; 
         //if you would like to re-use this data source, I would suggest making this as a   
         //property within this class 

        [g setSelection1:(int)path.row];
        [destController setMyData:g];
    }
}

在第二个表格中，声明一个属性：

@property (strong, nonatomic) Data *myData;

通过NSObject将数据UItable传递给UItable

2 个答案: