从mysql切换到PDO

时间:2013-10-06 08:39:54

标签: php mysql sql database pdo

正如标题所述,我正在从旧的MySQL_statements切换到PDO。我遇到问题但是在尝试查看'tableitem'是否已存在时,如果确实存在,我想抓住'tableitem2',如果'tableitem'不存在,我想设置'tableitem2'到1.这是我的旧MySQL代码,下面我将说明我尝试过的内容。

$user_ip = $_SERVER['REMOTE_ADDR'];
$query = "SELECT * FROM TABLENAME WHERE user_ip='$user_ip' ";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_row($result);
if (mysql_num_rows($result) )
{
  $_SESSION['stage'] = $row[1];
}
else
{
   $_SESSION['stage'] = 1;
    $strSQL2 = "INSERT INTO TABLENAME (user_ip, stage) VALUES ('$user_ip','$stage')";
     $result = mysql_query($query) or die(mysql_error());
}

以上工作,但现在我希望切换到PDO语句。 如果我尝试过PDO语句,那么这就是

$user_ip = $_SERVER['REMOTE_ADDR'];

$sql = "SELECT COUNT(`stage`) FROM `TABLENAME` WHERE `user_ip` = ?";
$result = $pdo->prepare($sql); 
$result->execute(array($user_ip)); 
$number_of_rows = $result->fetchColumn();

    /* Check the number of rows that match the SELECT statement */
  if ($result->fetchColumn() > 0) {
        $_SESSION['stage'] = $row[1];
         }
  else {
      $_SESSION['stage'] = 1;
    $result = $pdo->prepare("INSERT INTO `BPGUV` (`user_ip`, `stage`) VALUES (:user_ip, :stage)";
    $result->execute(
        array(
        ':user_ip' => $user_ip,
        ':stage' => 1
        )
    );
}

非常感谢任何帮助,我已经使用PDO连接到数据库,并且能够使用PDO使用MySQL命令,似乎无法将上述代码正确地转移到PDO语句中。

1 个答案:

答案 0 :(得分:1)

$user_ip = $_SERVER['REMOTE_ADDR'];
$sql = "SELECT COUNT(`stage`) FROM `TABLENAME` WHERE `user_ip` = ?";
$result = $con->prepare($sql);
$result->execute(array($user_ip)); 
$number_of_rows = $result->fetchColumn();
  /* Check the number of rows that match the SELECT statement */
  if ($number_of_rows > 0) {
        $_SESSION['stage'] = $number_of_rows;
 }
  else {
    $_SESSION['stage'] = 1;
    $result = $pdo->prepare("INSERT INTO `TABLENAME` (`user_ip`, `stage`) VALUES (:user_ip, :stage)");
    $result->execute(
        array(
        ':user_ip' => $user_ip,
        ':stage' => 1
        )
    );
}

在第一个查询中,您直接在查询中传递$user_ip,而不是稍后绑定它或作为参数传递。目前,该查询被视为:

SELECT COUNT(`stage`) 
FROM `TABLENAME` 
WHERE `user_ip` = 8.8.8.8

如你所知,语法错误。