Question

我有一个简单的应用程序，在主选项卡上，我有一个按钮。单击按钮时，它会启动另一个选项卡。但是当我点击按钮时，屏幕变为空白，并显示：

不幸的是，appname已停止

我哪里出错了？

代码段包括：

MainActivity.Java

   public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
}

public void serveMenu(View view) {
  // Do something in response to button
Intent intent = new Intent(this, ServeMenuActivity.class);
startActivity(intent);

  }
    }

ServeMenuActivity.Java

 import android.app.Activity;
 import android.content.Intent;
 import android.os.Bundle;
 import android.view.Menu;

   public class ServeMenuActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_serve_menu);
Intent intent = getIntent();
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.serve_menu, menu);
return true;
 }

   }

AdriodManifest.xml

        <category android:name="android.intent.category.LAUNCHER" />
    </intent-filter>
</activity>
<activity
    android:name="com.mywinsystems.tkrctennistips.ServeMenuActivity"
    android:label="@string/title_activity_serve_menu" >

</activity>

Answer 1

检查是否在main.xml按钮上添加了onClick serveMenu，即android:onClick="serveMenu"

Answer 2

10-06 17:30:41.249: D/OpenGLRenderer(18009): Enabling debug mode 0 10-06 17:31:46.774: D/AndroidRuntime(18009): Shutting down VM 10-06 17:31:46.774: W/dalvikvm(18009): threadid=1: thread exiting with uncaught exception (group=0x4108f2a0) 10-06 17:31:46.784: E/AndroidRuntime(18009): FATAL EXCEPTION: main 10-06 17:31:46.784: E/AndroidRuntime(18009): java.lang.IllegalStateException: Could not find a method ServeMenu(View) in the activity class com.mywinsystems.tkrctennistips.MainActivity for onClick handler on view class android.widget.Button with id 'button1'

根据你上面的locgcate 尝试重命名

public void serveMenu(View view) {
  // Do something in response to button
Intent intent = new Intent(this, ServeMenuActivity.class);
startActivity(intent);

  }

到

public void ServeMenu(View view) {
  // Do something in response to button
Intent intent = new Intent(this, ServeMenuActivity.class);
startActivity(intent);

  }

当我单击按钮调用第二个活动时，为什么我的应用程序停止工作？

2 个答案: