Question

我正在创建Phonegap应用程序，并想检测是否有人按下了Android设备的硬件菜单按钮。

这是我的简单HTML代码，几乎与helloworld app相同：

<!DOCTYPE html>
<!--
    Licensed to the Apache Software Foundation (ASF) under one
    or more contributor license agreements.  See the NOTICE file
    distributed with this work for additional information
    regarding copyright ownership.  The ASF licenses this file
    to you under the Apache License, Version 2.0 (the
    "License"); you may not use this file except in compliance
    with the License.  You may obtain a copy of the License at

    http://www.apache.org/licenses/LICENSE-2.0

    Unless required by applicable law or agreed to in writing,
    software distributed under the License is distributed on an
    "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
     KIND, either express or implied.  See the License for the
    specific language governing permissions and limitations
    under the License.
-->
<html>
    <head>
    <meta charset="utf-8" />
    <meta name="format-detection" content="telephone=no" />
    <meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width, height=device-height, target-densitydpi=device-dpi" />
    <link rel="stylesheet" type="text/css" href="css/index.css" />
    <title>Hello World</title>
    </head>
    <body>
    <div class="app">
        <h1>PhoneGap</h1>
        <div id="deviceready" class="blink">
            <p class="event listening">Connecting to Device</p>
            <p class="event received">Device is Ready</p>
        </div>

        <div id="testapp">Here</div>
    </div>
    <script type="text/javascript" src="phonegap.js"></script>
    <script type="text/javascript" src="js/index.js"></script>
    <script type="text/javascript">
        app.initialize();
    </script>
    </body>
</html>

这是JS，它有逻辑：

/*
 * Licensed to the Apache Software Foundation (ASF) under one
 * or more contributor license agreements.  See the NOTICE file
 * distributed with this work for additional information
 * regarding copyright ownership.  The ASF licenses this file
 * to you under the Apache License, Version 2.0 (the
 * "License"); you may not use this file except in compliance
 * with the License.  You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing,
 * software distributed under the License is distributed on an
 * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
 * KIND, either express or implied.  See the License for the
 * specific language governing permissions and limitations
 * under the License.
 */
var app = {
    // Application Constructor
    initialize: function() {
    this.bindEvents();
    },
    // Bind Event Listeners
    //
    // Bind any events that are required on startup. Common events are:
    // 'load', 'deviceready', 'offline', and 'online'.
    bindEvents: function() {
    document.addEventListener('deviceready', this.onDeviceReady, false);
    document.addEventListener('menubutton', this.onMenuButton, false);
    },
    // deviceready Event Handler
    //
    // The scope of 'this' is the event. In order to call the 'receivedEvent'
    // function, we must explicity call 'app.receivedEvent(...);'
    onDeviceReady: function() {
    app.receivedEvent('deviceready');
    },
    onMenuButton:  function(){
    app.menuPressed();
    },
    // Update DOM on a Received Event
    receivedEvent: function(id) {
    var parentElement = document.getElementById(id);
    var listeningElement = parentElement.querySelector('.listening');
    var receivedElement = parentElement.querySelector('.received');

    listeningElement.setAttribute('style', 'display:none;');
    receivedElement.setAttribute('style', 'display:block;');



    console.log('Received Event: ' + id);
    },
    menuPressed: function(){
document.getElementById("testapp").innerHTML = "it is in menu div";
    }
};

此处检测何时检测到deviceready，但未检测到menubutton检测。

请让我知道我做错了什么。

感谢

Answer 1

我找到了原因，因为它没有检测到menubutton事件。我实际上是在错误的地方附加事件监听器。

这一行：

document.addEventListener('menubutton', this.onMenuButton, false);

而不是bindEvents，它应该在onDeviceReady函数中，因为在onDeviceReady中我们可以附加事件。但我们无法在bindEvents中将其附加到bindEvents仅执行一次，app.initialize从index.html调用。

让我知道是否有人需要了解更多信息，以便它对您有用。

Answer 2

我在函数定义中省略了参数 ev ，打破了我的整个应用程序。不知道为什么，但是当我把它放回去时它就修复了一切！这是Phonegap 3.1.0。

document.addEventListener("menubutton", native_menu_button, false);

function native_menu_button(ev) {
    //whatever
}

Phonegap应用程序未检测到Android硬件Menubutton事件

2 个答案: