Question

我一直试图找出如何通过嵌套数组进行循环。

我有一个名为worldShapes的数组，它包含子数组。我想循环通过父数组并从中获取所有子数组。

这是我的尝试：

//Nested array

worldShapes = [

[33,108,66,141,99,174,99,207,132,207,165,207,165,240],

[132,306,165,306,165,339,165,372,132,405,99,405,99,438,132,438,165,438],

[198,339,231,339,264,372,297,372,330,405,363,438,396,438],

[198,174,198,273,231,306,264,306],

[231,174,231,240,264,273,297,273],

[396,306,462,306,495,339,495,372,528,405,528,438,561,438,594,471],

[660,504,561,504,495,504]

];

//trying to loop trough each item in the child array

(function(){
    var wShapes = worldShapes; //create a local variable
    var wLen = wShapes.length; //store the length as a variable

        for (var i = 0; i < wLen; i++) {
            for (var j = 0; j < wShapes[i].length; j++){
            console.log(wShapes[i][j]); //this is propably wrong, trying to access the current child item of the current parent array 
            }
        }
    })

Answer 1

只需将();添加到代码的最后; - ）

您只是忘记调用匿名函数

Answer 2

要执行此功能，请添加()

(function () {
    var wShapes = worldShapes; //create a local variable
    var wLen = wShapes.length; //store the length as a variable

    for (var i = 0; i < wLen; i++) {
        for (var j = 0; j < wShapes[i].length; j++) {
            console.log(wShapes[i][j]); //this is propably wrong, trying to access the current child item of the current parent array 
        }
    }
}()); // here

Fiddle

嵌套数组for循环

2 个答案: