真的不知道你能否,但我需要DATE VENC等于'2013-02-02'。 列date_pay:
的值1-2013-01-01
2-2013-02-02
3-0000-00-00
4-0000-00-00
这是我的疑问:
SELECT s.id,
s.name,
s.nro_s,
ts.cat,
SUM( ts.pryce ) AS deuda,
SUM( ts.pryce ) DIV ts.pryce AS c_p,
date_venc = (select max(date_pay) from c ) // the date in question
FROM s
INNER JOIN c
INNER JOIN ts
WHERE s.id = '123'
AND c.id = '123'
AND c.date_pay = '0000-00-00'
AND s.ts = ts.id_ts
对不起我的英语,非常基础。 问候。
答案 0 :(得分:1)
假设date_venc是DATE可能的解决方案
select *
from s
where s.date_venc=
(select max(cast(SUBSTRING_INDEX(date_pay,'-',-3)as DATE))from c);
also check out sqlfiddle
http://sqlfiddle.com/#!2/64197/1
并且您的查询可能应该修改为,
SELECT s.id,
s.name,
s.nro_s,
ts.cat,
SUM( ts.pryce ) AS deuda,
SUM( ts.pryce ) DIV ts.pryce AS c_p,
date_venc
FROM s
INNER JOIN c
INNER JOIN ts
WHERE s.id = '123'
AND c.id = '123'
AND c.date_pay = '0000-00-00'
AND s.ts = ts.id_ts
AND date_venc = (select max(cast(SUBSTRING_INDEX(date_pay,'-',-3)as DATE)) from c ) // the date in question