Question

我正在阅读一个维基百科XML文件，我必须删除任何列表项。例如。对于以下字符串：

String text = ": definition list\n
** some list item\n
# another list item\n
[[Category:1918 births]]\n
[[Category:2005 deaths]]\n
[[Category:Scottish female singers]]\n
[[Category:Billy Cotton Band Show]]\n
[[Category:Deaths from Alzheimer's disease]]\n
[[Category:People from Glasgow]]";

在这里，我想要删除*，#和:，而不是删除类别的那个。输出应如下所示：

String outtext = "definition list\n
some list item\n
another list item\n
[[Category:1918 births]]\n
[[Category:2005 deaths]]\n
[[Category:Scottish female singers]]\n
[[Category:Billy Cotton Band Show]]\n
[[Category:Deaths from Alzheimer's disease]]\n
[[Category:People from Glasgow]]";

我使用以下代码：

Pattern pattern = Pattern.compile("(^\\*+|#+|;|:)(.+)$");
            Matcher matcher = pattern.matcher(text);
            while (matcher.find()) {
                String outtext = matcher.group(0);
                outtext = outtext.replaceAll("(^\\*+|#+|;|:)\\s", "");
                return(outtext);
                }

这不起作用。你能说明我应该怎么做吗？

Answer 1

这应该有效：

text = text.replaceAll("(?m)^[*:#]+\\s*", "");

重要的是在此使用(?m) MULTILINE模式，可让您为每一行使用行开始/结束锚点。

<强>输出：

definition list
some list item
another list item
[[Category:1918 births]]
[[Category:2005 deaths]]
[[Category:Scottish female singers]]
[[Category:Billy Cotton Band Show]]
[[Category:Deaths from Alzheimer's disease]]
[[Category:People from Glasgow]]

Java：正则表达式删除列表的维基标记

1 个答案: