Question

是否可以判断帖子是空的还是尚未发布？我知道

if($_POST['varible']!="") {
    $loginerr="";
} else  {
    $loginerr="Please check your entry.";
}

或

if(ifempty($_POST['varible']) {
    $loginerr="Please Check your Entry.";
} else {
    $loginerr="";
}

我只想要一种方法，判断是否已发送$ _POST。

Answer 1

$loginErr='';
if (!isset($_POST['variable']))
    $loginerr="Please Check your Entry.";

Answer 2

PHP isset用于检查数组中存在的行。 empty用于检查数组值。所以在这里，如果条件更好，我们可以使用这两个。

 if(isset($_POST['vaiable']) && !empty($_POST['vaiable'])){

 //Here all the condition is satisfied and the $_POST['vaiable'] definitely have some value

 }

Answer 3

要检查的语法是

if(isset($_POST['vaiable'])){code goes here}

要检查帖子是否为空，您可以按照以下语法进行检查

If(empty($_POST['vaiable'])){code goes here}


if(!empty($_POST['varible'])) {
    $loginerr="";
} else  {
    $loginerr="Please check your entry.";
}

Answer 4

试试此代码

if(empty($_POST['varible']))
{
    $loginerr="Please Check your Entry.";
} 
else 
{
    $loginerr = "";
}

Answer 5

使用PHP中的empty函数

if(empty($_POST['varible'])) {
    $loginerr = "Please Check your Entry.";
 } else {
    $loginerr = "";
 }

或isset函数

if(!isset($_POST['varible'])) {
    $loginerr = "Please Check your Entry.";
 } else {
    $loginerr = "";
 }

Answer 6

<?php
//save it in a variable
$variable = $_POST['variable'];
//now check
if(empty($variable )) {

echo "The field was empty";

}
else
{
//whatever you want
}
?>

如何判断帖子是发布还是空白

6 个答案: