如何在iOS中获取Linkedin访问令牌来调用API?

时间:2013-10-04 19:38:51

标签: ios api rest oauth linkedin

我有一个REST API,允许客户端使用Linkedin从Linkedin登录访问令牌。

我已经通过从Javascript API获取访问令牌并发送到登录来创建此服务,而不是api调用LinkedIn API来检索用户数据。这很好用,但我们在使用iOS生成的访问令牌时遇到了问题。

我们正在使用LinkedIn OAuth Sample Client在移动设备上登录LinkedIn,而不是我们获取访问令牌。使用该访问令牌,我们的API无法调用LinkedIn。

我的问题是:这是在API中使用LinkedIn API的正确方法吗?而且,如果是,我如何在iOS集成到我的API时生成正确的访问令牌?

1 个答案:

答案 0 :(得分:2)

您需要遵循简单的步骤 1.您需要请求LinkedIn授权用户。 (authorisation code将在此收到回复。)
2.使用授权代码,您需要向上面收到的authorisation code发送对LinkedIn的POST请求。

ViewDidLoad

-(void)viewDidLoad  
{  
#warning:- Please provide your clientID and clientSecret
linkedInKey = @"YOUR_CLIENT_ID_HERE";
linkedInSecret = @"YOUR_CLIENT_SECRET_HERE";
authorizationEndPoint = @"https://www.linkedin.com/uas/oauth2/authorization";
accessTokenEndPoint = @"https://www.linkedin.com/uas/oauth2/accessToken";  
#warning:- Please provide your redirectUrl here.
NSString *redirectURL = @"http://REDIRECT_URL_THAT_YOU_HAVE_PROVIDED_WHILE_REGISTERING_YOUR_APP";
encodedRdirectURL = [redirectURL stringByAddingPercentEncodingWithAllowedCharacters:NSCharacterSet.alphanumericCharacterSet];
_webView.delegate = self;
[self startAuthorisation];
}

-(void)startAuthorisation
{
// Specify the response type which should always be "code".
NSString *responseType = @"code";
// Create a random string
NSString *state = @"anyRandomString";
// Set preferred scope. It depends on your preference.
NSString *scope = @"w_share";
// Create the authorization URL string.
NSString *authorizationURL = [NSString stringWithFormat:@"%@?response_type=%@&client_id=%@&redirect_uri=%@&state=%@&scope=%@",authorizationEndPoint,responseType,linkedInKey,encodedRdirectURL,state,scope];

NSLog(@"%@",authorizationURL);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:authorizationURL]];
[_webView loadRequest:request];
}

#pragma mark- WebView Delegate.

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSURL *url = request.URL;
//here we will catch the response of the server which will redirect to our redirect url. Hence we first check for the host(which is our redirect url) then only extract the code.  
#warning:- Please provide your redirectUrl here.
if ([url.host isEqualToString:@"www.Your_redirect_url.com"])
{
    if ([url.absoluteString rangeOfString:@"code"].length)
    {

//response containing the authorisation code looks somehow like below.
    //http://www.Your_redirect_url.com?<strong>code=AQSetQ252oOM237XeXvUreC1tgnjR-VC1djehRxEUbyZ-sS11vYe0r0JyRbe9PGois7Xf42g91cnUOE5mAEKU1jpjogEUNynRswyjg2I3JG_pffOClk</strong>&state=linkedin1450703646

   //......obtaining the code from the response......//
        NSArray *urlParts = [url.absoluteString componentsSeparatedByString:@"?"];
        NSString *codePart = [urlParts objectAtIndex:1];
        NSArray *codeParts = [codePart componentsSeparatedByString:@"="];
        NSString *code = [codeParts objectAtIndex:1];
        [self requestforAccessToken:code];
    }
}
return YES;
}

- (void)requestforAccessToken:(NSString *)authorisationCode
{
NSString *grantType = @"authorization_code";
NSString *postParameter = [NSString stringWithFormat:@"grant_type=%@&code=%@&redirect_uri=%@&client_id=%@&client_secret=%@",grantType,authorisationCode,encodedRdirectURL,linkedInKey,linkedInSecret];
NSData *postdata = [postParameter dataUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:accessTokenEndPoint]];
request.HTTPMethod = @"POST";
request.HTTPBody = postdata;
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

AFURLSessionManager *manager = [[AFURLSessionManager alloc] initWithSessionConfiguration:[NSURLSessionConfiguration defaultSessionConfiguration]];


manager.responseSerializer = [AFJSONResponseSerializer
                              serializerWithReadingOptions:NSJSONReadingAllowFragments];


[[manager dataTaskWithRequest:request completionHandler:^(NSURLResponse  * response, id  responseObject, NSError * error )
  {
      if (!error)
      {
          NSLog(@"Reply JSON: %@", responseObject);
          NSString *accessToken = [responseObject objectForKey:@"access_token"];
          NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
          [defaults setObject:accessToken forKey:@"linkedInAccessToken"];
          [defaults synchronize];
      }

  }] resume];

}  

我在这里使用了AFNetworking库。所以请从gitHub获取库并将其添加到您的项目中。为此,您需要在viewController中导入AFHTTPSessionManager.h

#warning:- please declare these following strings as global variable under interface as.  
@interface WebViewController ()<UIWebViewDelegate>  
{
NSString *linkedInKey;
NSString *linkedInSecret;
NSString *authorizationEndPoint;
NSString *accessTokenEndPoint;
NSString *encodedRdirectURL;    
}

我还使用UIWebView并使用名为IBOutlet的{​​{1}}与webView相关联,您可以在上面的代码中找到它。

不要忘记确认UIWebViewDelegate。

希望这会有所帮助 祝你好运。