我正在使用class-extend.js在我的JS代码中实现简单继承:
var Man = Class.extend({
init: function(name) {
this.name = name;
}
});
var Mr = Man.extend({
init: function(name) {
this._super("Mr. " + name);
}
});
var mrBean = new Mr("Bean");
如何修改脚本以从没有class-extend.js实现的对象继承?
function AnotherMan(name) {
this.name = name;
}
...
?
答案 0 :(得分:2)
您可以在extend
功能上使用.call()
。这需要init
原型方法指向构造函数:
function AnotherMan(name) {
this.name = name;
}
AnotherMan.prototype.init = AnotherMan; // = AnotherMan.prototype.constructor;
var Mr = Class.extend.call(AnotherMan, {
init: function(name) {
this._super("Mr. " + name);
}
});
var mrBean = new Mr("Bean");
当然,使用原生Correct javascript inheritance而不是Class
库可能会更容易......
function AnotherMan(name) {
this.name = name;
}
function Mr(name) {
AnotherMan.call(this, "Mr. " + name);
}
Mr.prototype = Object.create(AnotherMan.prototype, {
constructor: {value: AnotherMan}
});
var mrBean = new Mr("Bean");
答案 1 :(得分:0)
以下内容将实现您的目标:(working jsFiddle)。它使用原型链来实现经典继承。
function AnotherMan(name) {
this.name = name;
}
function Mr(name) {
AnotherMan.call(this, name); // Call the superclass's constructor in the scope of this.
this.name = "Mr. " + name; // Add an attribute to Author.
}
Mr.prototype = new AnotherMan(); // Set up the prototype chain.
Mr.prototype.constructor = Mr; // Set the constructor attribute to Mr.
var mrBean = new Mr("Bean");
您可以将其概括为一个函数:(Another Working jsFiddle)
function extend(subClass, superClass) {
var F = function() {};
F.prototype = superClass.prototype;
subClass.prototype = new F();
subClass.prototype.constructor = subClass;
subClass.superclass = superClass.prototype;
if(superClass.prototype.constructor == Object.prototype.constructor) {
superClass.prototype.constructor = superClass;
}
}
并像这样使用它:
function AnotherMan(name) {
this.name = name;
}
function Mr(name) {
Mr.superclass.constructor.call(this, name);
this.name = "Mr. " + name;
}
extend(Mr, AnotherMan);
var mrBean = new Mr("Bean");