Question

我需要一个简单的HTML2RTF转换器和我尝试运行以下代码....但我有一个错误的代码示例

代码：

import java.io.ByteArrayInputStream;
import java.io.StringWriter;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

import javax.swing.text.Document;
import javax.swing.text.html.HTMLEditorKit;
import javax.swing.text.rtf.RTFEditorKit;

public class converter {
    private static Pattern htmlTrimPattern = Pattern.compile(".*<body>(.*)</body>.*", Pattern.DOTALL);

    public static void main(String[] args)
    {


        toRtf("<!DOCTYPE html>\n" +
                "<html>\n" +
                "<body>\n" +
                "\n" +
                "<h1>My First Heading</h1>\n" +
                "\n" +
                "<p>My first paragraph.</p>\n" +
                "\n" +
                "</body>\n" +
                "</html>\n");

    }

    public static String toRtf(String html) {
        ByteArrayInputStream input= new ByteArrayInputStream(html.getBytes());
        StringWriter writer = new StringWriter();
        try {
            RTFEditorKit rtfEditorKit = new RTFEditorKit();
            HTMLEditorKit htmlEditorKit = new HTMLEditorKit();
            Document htmlDoc = htmlEditorKit.createDefaultDocument();
            htmlEditorKit.read(input, htmlDoc, 0);
            rtfEditorKit.write(writer, htmlDoc, 0, htmlDoc.getLength());
        } catch (Exception ex) {
            System.out.println("Error"+ex);
        }
        System.out.println(writer.toString());
        return writer.toString();
    }
}

错误：

Errorjava.io.IOException: RTF is an 8-bit format

我做错了什么？谷歌在这种情况下不是我的朋友，我希望你可以帮助我:)。

Answer 1

RTF是一种8位格式，但您要将内容发送到Writer，这是“用于写入字符流的类”。尝试使用write()的{{1}}变体：

ByteArrayOutputStream

控制台：

{\rtf1\ansi
{\fonttbl\f0\fnil Monospaced;}

\par
My First HeadingMy first paragraph.\par
}

javax.swing.text.rtf.RTFEditorKit / RTF是一种8位格式

1 个答案: