Question

我在SQL Server中需要一个WHERE条件，我可以从给定日期返回过去7天的活动。

假装我有2列日期[dateA]和[dateB]

我正在寻找像

这样的东西

SELECT *
FROM TABLE
WHERE [dateB] >= ([dateA] - 7 days)

Answer 1

WHERE dateB >= DATEADD(DAY, -7, dateA)

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Answer 2

select * from table
where dateB >= dateadd(dd,-7, dateA)

Answer 3

SELECT * FROM TABLE WHERE [dateB]）＆gt; = convert（datetime，[dateA] - 7）

你是如此亲密

Answer 4

    IF you need past 7 days activity then you need take difference of date in that column from today i.e GETDATE() it will be something like this......

 WHERE (DATEDIFF(DAY, GETDATE(), dateA) <= 0 AND DATEDIFF(DAY, GETDATE(), dateA) > -7 ) 
        AND (DATEDIFF(DAY, GETDATE(), dateB) <= 0 AND DATEDIFF(DAY, GETDATE(), dateB) > -7 )

SQL Server：在日期的X天内返回记录

4 个答案: