PHP:json_decode

时间:2013-10-04 16:13:29

标签: php json

我必须解析json字符串中的值,如下所示:

[{"type":"list","value":["A","B"],"field":"scheda"}] 

我怎样才能使用PHP函数json_decode

例如我想要打印:

field = "scheda"
values = "A,B"

2 个答案:

答案 0 :(得分:4)

$json = json_decode('[{"type":"list","value":["A","B"],"field":"scheda"}]');
print 'field = "'.$json[0]->field.'"'."\n";
print 'values = "'.implode(",",$json[0]->value).'"'."\n";

答案 1 :(得分:0)

如果您不能使用json_decode(),为什么不尝试上课?

例如,...... http://www.phpclasses.org/package/4205-PHP-Serialize-and-unserialize-values-in-JSON-format.html