我一直在
#1062 - Duplicate entry '0' for key 'PRIMARY'
错误。
它只是一个标准的简单查询
UPDATE ivrecord SET title = 'sometitle' WHERE ID ='125'
事情是,我根本不更新主键。
15个数据库中只有1个表。
查询实际上有效,进行更新,但无论如何都会抛出错误..我唯一可以编写代码的方法是尝试/捕获错误。
提前感谢。
编辑显示'show table'输出
CREATE TABLE `ivrecord` ( `ID` int(10) NOT NULL AUTO_INCREMENT, `courseID`
varchar(30) COLLATE latin1_general_ci NOT NULL DEFAULT '0', `unitID` char(3)
COLLATE latin1_general_ci NOT NULL DEFAULT '0', `assNo` int(3) NOT NULL DEFAULT
'0', `title` varchar(255) COLLATE latin1_general_ci NOT NULL DEFAULT '',
`verifierID` int(3) NOT NULL DEFAULT '0', `authorID` int(3) NOT NULL DEFAULT
'0', `IVdate` varchar(50) COLLATE latin1_general_ci NOT NULL DEFAULT '', `IVref`
varchar(30) COLLATE latin1_general_ci NOT NULL DEFAULT '', `issueDate` char(15)
COLLATE latin1_general_ci DEFAULT '0', `dueDate` char(15) COLLATE
latin1_general_ci DEFAULT '0', `Q3` char(3) COLLATE latin1_general_ci DEFAULT
'0', `Q4` char(3) COLLATE latin1_general_ci DEFAULT '0', `Q5` char(3) COLLATE
latin1_general_ci DEFAULT '0', `feedback` text COLLATE latin1_general_ci NOT
NULL, `passes` varchar(150) COLLATE latin1_general_ci NOT NULL DEFAULT '',
`merits` varchar(150) COLLATE latin1_general_ci NOT NULL DEFAULT '', `dists`
varchar(150) COLLATE latin1_general_ci NOT NULL DEFAULT '', `version` int(3) NOT
NULL DEFAULT '1', `url` varchar(200) COLLATE latin1_general_ci NOT NULL DEFAULT
'', `void` tinyint(1) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`), FULLTEXT KEY
`feedback` (`feedback`)) ENGINE=MyISAM AUTO_INCREMENT=895 DEFAULT CHARSET=latin1
COLLATE=latin1_general_ci