我正在努力获取python / tkinter标签小部件来更新其内容。根据今天的早期帖子,我按照如何组合小部件的说明进行操作。但是,在运行时,标签小部件不会更改内容,而只是保留其原始内容。据我所知,从来没有调用decrement_widget()。有什么想法吗?
def snooze (secs):
"""
Snoozes for the given number of seconds. During the snooze, a progress
dialog is launched notifying the
"""
root = Tkinter.Tk()
prompt = 'hello'
label1 = Tkinter.Label(root, text=prompt, width=len(prompt))
label1.pack()
remaining = secs
def decrement_label ():
text = "Snoozing %d sec(s)" % remaining
remaining -= 1
label1.config(text=text, width=100)
label1.update_idletasks()
for i in range(1, secs + 1):
root.after(i * 1000, decrement_label )
root.after((i+1) * 1000, lambda : root.destroy())
root.mainloop()
答案 0 :(得分:22)
您需要使用StringVar
设置标签textvariable
;当StringVar
更改时(通过调用myStringVar.set("text here")
),标签的文本也会更新。是的,我同意,这是一种奇怪的做事方式。
有关详细信息,请参阅the Tkinter Book:
您可以将Tkinter变量与标签相关联。当变量的内容发生变化时,标签会自动更新:
v = StringVar() Label(master, textvariable=v).pack() v.set("New Text!")
答案 1 :(得分:6)
我认为你得到了一个“在赋值前引用”错误,因为Python认为remaining
在本地范围内。
在Python 3中,您可以说nonlocal remaining
。但是在Python 2中,我不相信有一种方法可以引用非本地的非全局范围。这对我有用:
remaining = 0
def snooze (secs):
"""
Snoozes for the given number of seconds. During the snooze, a progress
dialog is launched notifying the
"""
global remaining
root = Tkinter.Tk()
prompt = 'hello'
label1 = Tkinter.Label(root, text=prompt, width=len(prompt))
label1.pack()
remaining = secs
def decrement_label ():
global remaining
text = "Snoozing %d sec(s)" % remaining
remaining -= 1
label1.config(text=text, width=100)
label1.update_idletasks()
for i in range(1, secs + 1):
root.after(i * 1000, decrement_label )
root.after((i+1) * 1000, lambda : root.destroy())
root.mainloop()
答案 2 :(得分:0)
import tkinter
from tkinter import *
# just init some vars
remaining = 0
secs = 0
root = tkinter.Tk()
prompt = StringVar()
def snooze (secs):
"""
Snoozes for the given number of seconds. During the snooze, a progress
dialog is launched notifying the
"""
def decrement_label ():
global remaining, prompt
remaining -= 1
prompt.set('Snoozing %d sec(s)' % remaining)
label1.update_idletasks()
if not remaining:
print("end ... ")
root.destroy()
global remaining
prompt.set("hello")
label1 = tkinter.Label(root, textvariable=prompt, width=30)
label1.pack()
remaining = secs
for i in range(1, secs + 1):
root.after(i * 1000, decrement_label )
snooze(10)
root.mainloop()
答案 3 :(得分:0)
要更新标签中的文本,您可以尝试以下操作:
from tkinter import *
root = Tk()
root.title("Title")
root.geometry('300x300')
def clear_text(self):
txtE.delete(0, 'end')
def new_label(event=None):
Entree = txtE.get()
lbl1['text'] = Entree.title()
clear_text(txtE)
lbl1 = Label(root, text='Hello There')
lbl1.pack()
txtE = Entry(root)
txtE.focus()
txtE.pack()
Button(root, text='Enter', command=new_label).pack()
Button(root, text='Quit', command=root.destroy).pack(side=BOTTOM)
root.bind('<Return>', new_label)
root.mainloop()
答案 4 :(得分:0)
我认为您必须调用snooze(secs)
函数
之后,如果您的代码再次不起作用,请尝试
设置变量
Variable = StringVar()
在标签小部件中,您可以将“ textvariable”参数设置为上述“ Variable”。
例如:
label1 = Label(root,textvariable = Variable).pack()
您可以通过将新值设置为“变量”进行更新
例如: Variable.set("hi")
希望你知道了!