Question

我可以看到我和How can I update a Tkinter canvas in the middle of a function call?有类似的问题，但我无法将接受的答案翻译成我的情况。在那个SO答案中，原则上调用自身的函数的解决方案很好，但我需要将一个列表a传递给函数，而不仅仅是调用它。

顺便说一句，是的，我知道该程序有效：打印列表a这是＃{1}}中的第一行＃'d工作得很好

问题：我如何让Tkinter将列表def renderGUI(a):（0表示灯关闭）动画为ons和offs？

请注意我也尝试了a，虽然有些偷看似乎对这种做法很不满意。

代码在

之下

提前多多感谢：

w.update_idletasks()

Answer 1

要使您的程序正常运行，只需在函数内部进行for循环，然后通过after调用它：

def f():
    for i in range (0,numLights):
        master.after(100, renderGUI(a))
        w.update_idletasks()    
        for n in range(0,numLights):
            if a[n]>1:
                a[n] = a[n]-1
            elif a[n] == 1:
                    #then its about to become nought, right?
                    a[n-1] = speed[n]
                    speed[n-1] = speed[n]
                    a[n] = a[n]-1
                    continue
            continue

btn = Button(master, text='Stop', width=20, command=master.destroy)
btn.pack()
master.after(1, f)
master.mainloop()

但是，如果你想摆脱update_idletasks，你可以使用一个协同程序（在这里包装成装饰器）：

def updatesdisplay(root, t=0):
    def _updatesdisplay(func):
        def driver(iterator):
            try: next(iterator)
            except StopIteration: pass
            else: 
                if t: root.after(t, driver, iterator)
                else: root.after_idle(driver, iterator)
        def wrapped():
            driver(func())
        return wrapped
    return _updatesdisplay

@updatesdisplay(master, 100) # 100 because we want to slow things down a bit
def f():
    for i in range (0,numLights):
        renderGUI(a)
        yield # window gets updated here
        for n in range(0,numLights):
            if a[n]>1:
                a[n] = a[n]-1
            elif a[n] == 1:
                    #then its about to become nought, right?
                    a[n-1] = speed[n]
                    speed[n-1] = speed[n]
                    a[n] = a[n]-1
                    continue
            continue

btn = Button(master, text='Stop', width=20, command=master.destroy)
btn.pack()
master.after(1, f)
master.mainloop()

Tkinter需要更新canvas中间进程。它只在完成时更新

1 个答案: