我有一个包含字符串的数组。这就像:
String[] stops = {
"Bangalore International Exhibition Center", "Jindal", "Manjunathnagar", "Nagasandra", "Dasarahalli", "Jalahalli", "Peenya Industry", "Peenya", "Yeswanthpur Industry", "Yeswanthpur", "Sandal Soap Factory", "Mahalaxmi", "Rajajinagar", "Kuvempu Road", "Srirampura", "Sampige Road", "Kempegowda Interchange", "Chikpet", "K R Market", "National College", "Lalbagh", "South End Circle", "Jayanagar", "R V Road Interchange", "Banashankari", "J P Nagar", "Puttenahalli", "Anjanapura Cross Road", "Krishna Leela Park", "Vajrahalli", "Thaighattapura", "Anjanapura/NICE Junction", "Kengeri", "R V College of Engineering", "Bangalore University Cross", "Rajarajeshwari Nagar", "Nayandahalli", "Mysore Road", "Deepanjali Nagar", "Attiguppe", "Vijayanagar", "Hosahall1i", "Magadi Road", "Sir M Vishweshwariah", "Vidhana Soudha", "M G Road Interchange", "Trinity", "Halasuru", "Indiranagar", "S V Road", "Baiyyappanahalli", "Jyotipura", "K R Puram", "Mahadevpura", "Garudacharpalya", "Doddanekkundi Induatrial State", "Vishweshwariah Industrial State", "Kundanahalli", "Vydhehi Hospital", "Satya Sai Medical Institute", "ITPB", "Kadugodi Industrial Area", "Ujjwal Vidhyalaya", "Whitefield", "Nagawara", "Arabic College", "Venkateshpura", "Tannery Town", "Pottery Town", "Cantonment Railway Station", "Shivajinagar", "Vellara Junction", "Langford Town", "Mico Bosch", "Dairy Circle", "Swagath Road Cross", "Jayadeva Hospital Interchange", "J P Nagar 4th Phase", "IIMB", "Hulimavu", "Gottigere", "Ragigudda Temple", "BTM Layout", "Silk Board", "HSR Layout", "Oxford College", "Muneshwara Nagar", "Chikkabegur", "Basapura Road", "Hosa Road", "Electronics City 1", "Electronics City 2", "Huskur Road", "Hebbagodi", "Bommasandra"
};
现在我有一个TextView。我想知道,如何检查用户在TextView中输入的值是否来自该字符串数组。如果没有,它应该提示用户进行更正。
答案 0 :(得分:3)
if(check(textView.getText.toString())){
//do somethingif true
}else{
//else
}
public boolean check(String text){
for(String s: stops){
if(s.equalsIngoreCase(text)){
return true;
}
}
return false;
}
答案 1 :(得分:2)
写一个这样的函数来检查你的字符串数组中是否存在输入,如果它返回false,则要求用户进行更正,否则就做你想做的事。
public boolean check(String input){
for(String s: stops){
if(s.equalsIngoreCase(input)){
return true;
}
}
return false;
}
像AlertDialog一样使用它来查看如何在android
中完成警报答案 2 :(得分:1)
试试这个
String s = obj_tv.getText().toString();
String[] stops = {
"Bangalore International Exhibition Center", "Jindal", "Manjunathnagar", "Nagasandra", "Dasarahalli", "Jalahalli", "Peenya Industry", "Peenya", "Yeswanthpur Industry", "Yeswanthpur", "Sandal Soap Factory", "Mahalaxmi", "Rajajinagar", "Kuvempu Road", "Srirampura", "Sampige Road", "Kempegowda Interchange", "Chikpet", "K R Market", "National College", "Lalbagh", "South End Circle", "Jayanagar", "R V Road Interchange", "Banashankari", "J P Nagar", "Puttenahalli", "Anjanapura Cross Road", "Krishna Leela Park", "Vajrahalli", "Thaighattapura", "Anjanapura/NICE Junction", "Kengeri", "R V College of Engineering", "Bangalore University Cross", "Rajarajeshwari Nagar", "Nayandahalli", "Mysore Road", "Deepanjali Nagar", "Attiguppe", "Vijayanagar", "Hosahall1i", "Magadi Road", "Sir M Vishweshwariah", "Vidhana Soudha", "M G Road Interchange", "Trinity", "Halasuru", "Indiranagar", "S V Road", "Baiyyappanahalli", "Jyotipura", "K R Puram", "Mahadevpura", "Garudacharpalya", "Doddanekkundi Induatrial State", "Vishweshwariah Industrial State", "Kundanahalli", "Vydhehi Hospital", "Satya Sai Medical Institute", "ITPB", "Kadugodi Industrial Area", "Ujjwal Vidhyalaya", "Whitefield", "Nagawara", "Arabic College", "Venkateshpura", "Tannery Town", "Pottery Town", "Cantonment Railway Station", "Shivajinagar", "Vellara Junction", "Langford Town", "Mico Bosch", "Dairy Circle", "Swagath Road Cross", "Jayadeva Hospital Interchange", "J P Nagar 4th Phase", "IIMB", "Hulimavu", "Gottigere", "Ragigudda Temple", "BTM Layout", "Silk Board", "HSR Layout", "Oxford College", "Muneshwara Nagar", "Chikkabegur", "Basapura Road", "Hosa Road", "Electronics City 1", "Electronics City 2", "Huskur Road", "Hebbagodi", "Bommasandra"
};
for(int i = 0; i < stops.length; i++)
{
if(stops[i].equalsIgnoreCase(s))
{
// do something
}
else
{
// do something
}
答案 3 :(得分:1)
public boolean checkavailability(String input)
{
for(String s: stops){
if(s.equalsIngoreCase(input))
{
return true;
}
}
return false;
}
使用此功能。