Question

我想在我的程序中使用响应代码请告诉我以下代码中的错误

  public class Main{
      public static void main(String args[]) throws Exception {
        URL url = new URL("http://www.google.com");
        HttpURLConnection httpCon = openConnection();


        System.out.println("Response code is " + httpCon.getResponseCode());
     }
    }

Answer 1

public class Main{
  public static void main(String args[]) throws Exception {
    URL url = new URL("http://www.google.com");
    HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();


    System.out.println("Response code is " + httpCon.getResponseCode());
 }
}

Answer 2

错误很明显。

openConnection()是URL类的一种方法，在您的班级中未定义。您必须使用之前创建的URL类对象。

调用openConnection（）方法必须是这样的 -

url.openConnection()它返回一个URLConnection对象，您必须将此对象强制转换为HttpURLConnection。

Answer 3

该问题的

原因是编译器告诉类构造函数（URL）和方法（openConnection ..）抛出异常（在signatures中定义）并采取一些必要的步骤。

您有两个选择：

Throw来自主方法的已检查异常。

public static void main(String[] args) throws IOException {
            URL url = new URL("http://www.google.com");
            HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
                System.out.println("Response code is " +
                                              httpCon.getResponseCode());
             }

或

使用Exception

抓住try catch block.

public static void main(String[] args) {
        URL url;
        HttpURLConnection httpCon;
        try {
            url = new URL("http://www.google.com");
            httpCon = (HttpURLConnection) url.openConnection();
            System.out.println("Response code is " + httpCon.getResponseCode());
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

Answer 4

你忘了放url 将其更改为HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();

package naveed.workingfiles;

import java.net.HttpURLConnection;
import java.net.URL;

public class Url {

    public static void main(String args[]) throws Exception {
        URL url = new URL("http://www.google.com");
        HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();

        System.out.println("Response code is " + httpCon.getResponseCode());
    }
}

Answer 5

尝试将对象强制转换为HttpURLConnection

public class Main{
  public static void main(String args[]) throws Exception {
    URL url = new URL("http://www.google.com");
    //Cast the object to  HttpURLConnection
    HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
    System.out.println("Response code is " + httpCon.getResponseCode());
 }
}

如何在java中获取响应代码

5 个答案: