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Question

我创建了一个循环，用于提取有关用户活动的信息。代码在作者页面上，我想要的是获取当前作者ID，因此根据用户所在的作者页面，它将获取该作者的ID。

见下文，我希望AUTHOR-ID成为当前作者的ID。

<script type="text/javascript">
                            var pieData = [
                            <?php

                            $user_id = AUTHOR-ID;

                            /* Get all categories */
                            $rand = array('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f');


                            $categories = get_terms( 'category', 'orderby=count&hide_empty=0' );

                            /* Loop for each category to count the posts of the user */
                            foreach($categories as $category)
                            {
                            $color = '#'.$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)];
                               $cat_name = $category->name;
                               $cat_id = $category->term_id;
                               $post_count = count(get_posts("cat=$cat_id&post_author=$user_id"));

                               echo "

                                            {
                                                value: ".$post_count.",
                                                color:'".$color."',
                                                label: ".$user_id."
                                            },";

                            }
                            ?>
                            ]
                            var myPie = new Chart(document.getElementById("piec").getContext("2d")).Pie(pieData);
                        </script>

Answer 1

试试这个：

<?php $author_id=$post->post_author; ?>

它将为您提供当前作者ID。

或者这个会帮助你更多：

global $current_user;
get_currentuserinfo();                      

$args = array(
    'author'        =>  $current_user->ID, // I could also use $user_ID, right?        
    );

// get his posts 'ASC'
$current_user_posts = get_posts( $args );

感谢。

Answer 2

<?php the_author_meta( 'ID' ); ?>

可能更好。

参考：the_author_meta

Answer 3

在作者档案中，以下内容将获得作者ID：

$author_ID = get_query_var('author');

这将为您提供更多信息：

$pageobj = get_queried_object();

参考：

http://codex.wordpress.org/Function_Reference/get_query_var
http://codex.wordpress.org/Function_Reference/get_queried_object

Answer 4

试试这个

global $wp_query;
$thePostID = $wp_query->post->ID;
$postdata = get_postdata($thePostID);
$authorID = $postdata['Author ID'];

或类似的东西

<?php $author_id=$post->post_author; ?>
<img src="<?php echo the_author_meta( 'avatar' , $author_id ); ?> " width="140" height="140" class="avatar" alt="<?php echo the_author_meta( 'display_name' , $author_id ); ?>" />
<?php echo the_author_meta( 'user_nicename' , $author_id ); ?>

Answer 5

这里的工作代码

<script type="text/javascript">
                            var pieData = [
                            <?php
                                $user_id = get_query_var('author');

                                $rand = array('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f');

                                //get all posts from author
                                $args = array(
                                    'post_type' => 'post',
                                    'author'=> $queried_object->ID
                                );

                                $the_query = new WP_Query( $args );

                                if ( $the_query->have_posts() ) :

                                    while ( $the_query->have_posts() ) : $the_query->the_post();

                                        //put categories in array
                                        $cat = get_the_category( get_the_ID() );
                                        $terms[] = $cat[0]->term_id;

                                    endwhile;

                                    wp_reset_query();
                                endif;

                                //count matching categories (array vals)
                                $countVal = array_count_values($terms);
                                foreach($countVal as $count){

                                    $color = '#'.$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)].$rand[rand(0,15)];

                                    echo "  {
                                            value: ".$count.",
                                            color:'".$color."'
                                            },";
                                }

                            ?>
                            ]
                            var myPie = new Chart(document.getElementById("piec").getContext("2d")).Pie(pieData);
                        </script>

获取wordpress中帖子的作者ID

5 个答案:

参考：