以下是我的表格：
[UserMaster]
UserId Int，UserName Varchar（200），AddedBy Int
UserId EmpName AddedBy
1 admin 0
2 SubAdmin1 1
3 Vikas 2
4 Mohit 3
5 Atul 4
6 Vishal 2
7 Mani 3
8 Sunny 1
[SalesMaster]
SalesId Int，UserId Int（FK_UserMaster_UserId），Price Int
SalesId UserId Price StatusId
10 1 100 1
11 2 200 1
12 3 300 1
13 4 500 1
14 5 100 2
15 6 200 1
16 7 111 2
17 8 222 1
[SalesProducts]
SaleProductId Int，SaleId Int（FK_SaleMaster_SaleId），Quantity Int
SaleProductId SalesId Quantity
1 10 2
2 11 2
3 12 1
4 13 1
5 14 3
6 15 2
7 16 5
8 17 1
[输出]
结果集应该包含登录用户的销售额+他创建的用户以及他们创建的其他用户。
以下TotalSalesAmount是：
[SalesMaster] .Price * [SalesProducts] .Quantity
例如：UserId的总销售额：1是 100 * 2 + 200 * 2 + 300 * 1 + 500 * 1 + 100 * 3 + 200 * 2 + 111 * 5 + 222 * 1 = 2877
同样对于UserId：2是 200 * 2 + 300 * 1 + 200 * 2 + 500 * 1 + 111 * 5 + 200 * 2 = 2555
案例1：
如果（admin）UserId = 1将登录，我们需要显示以下
UserId TotalSalesAmount OwnSaleAmount AddedBy
1 2877 200 0
2 2555 400 1
3 1355 300 2
4 800 500 3
5 100*3= 300 300 4
6 200*2=200 200 2
7 111*5= 555 555 3
8 222*1= 222 222 1
案例2： 如果（Vikas）UserId = 3将登录，我们需要显示以下
UserId TotalSalesAmount OwnSaleAmount AddedBy
3 300*1 + 500*1 + 111*5= 1355 300 2
4 500*1 + 100*3= 800 500 3
5 100*3= 300 300 4
7 111*5= 555 555 3
我在这里使用了表脚本和数据 http://test-admin.teamberry.biz/SalesScript.rar ，
运行此脚本后，请执行以下查询，取UM.UserId = 164，SM.statusID = 1 UserId = 166的TotalSalesAmount是错误的，因为它的TotalSaleAmount应该与ownSaleAmount相同，即444，因为UserId = 166没有任何子项。
with tblOwnSaleAmount as
(
select UM.UserId,UM.EmpName,UM.AddedBy,cast(sum( SM.Price*SP.Quantity) as int) as OwnSaleAmount
from UserMaster UM
left join SalesMaster SM on SM.UserId = UM.UserId and SM.statusID = 1
left join SalesProducts SP on SP.SalesId = SM.SalesId
where UM.UserId = 164
group by UM.UserId ,UM.AddedBy,UM.EmpName
union all
select UM.UserId,UM.EmpName, UM.AddedBy,
case when SM.statusID = 1 then cast(( SM.Price*SP.Quantity ) as int)
else 0 end as OwnSaleAmount
from UserMaster UM
join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
join SalesMaster SM on SM.UserId = UM.UserId
join SalesProducts SP on SP.SalesId = SM.SalesId
)
, tbldistinctOwnSaleAmount as
(
select distinct UserId,EmpName, AddedBy,Isnull(OwnSaleAmount,0) as OwnSaleAmount
from tblOwnSaleAmount
)
,
tblTotalOwnSaleAmount as
(
select OSA.UserId,OSA.EmpName, OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
from tbldistinctOwnSaleAmount OSA --inner join tbldistinctOwnSaleAmount A on OSA.AddedBy = A.UserID
group by OSA.UserId ,OSA.AddedBy,OSA.EmpName
)
select OSA.*
, TotalSalesAmount = isnull(
(
select sum( OSA1.OwnSaleAmount )
from tblTotalOwnSaleAmount OSA1
where OSA1.UserId > OSA.UserId
), 0 )
+ OSA.OwnSaleAmount
from tblTotalOwnSaleAmount OSA
order by OSA.UserId
答案 0 :(得分：1)
如果我的理解错误，请更新：
如果我的上述理解是正确的，您可以通过使用公用表表达式的递归功能获得所需的结果，然后计算运行总计：
-- create a common table expression to get OwnSaleAmount for logged in user and all the users who are added由当前用户进一步提供。
with tblOwnSaleAmount as
(
select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount
from UserMaster UM
join SalesMaster SM on SM.UserId = UM.UserId
join SalesProducts SP on SP.SaleId = SM.SalesId
where UM.UserId = 1 -- Userid of logged in user which will act as anchor member
-- for later subqueries
union all
select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount
from UserMaster UM
join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
join SalesMaster SM on SM.UserId = UM.UserId
join SalesProducts SP on SP.SaleId = SM.SalesId
)
select OSA.*
, TotalSalesAmount = isnull(
(
select sum( OSA1.OwnSaleAmount )
from tblOwnSaleAmount OSA1
where OSA1.AddedBy > = OSA.UserId
), 0 )
+ OSA.OwnSaleAmount
from tblOwnSaleAmount OSA
order by OSA.UserId
编辑：更新了查询：
--1. Corrected joins in anchor query to fetch records for users who have no records in SalesMaster Table.
--2. IS it another requirement that user entries with status id = 2 should not be considered?
with tblOwnSaleAmount as
(
select UM.UserId, UM.AddedBy, sum( SM.Price*SP.Quantity ) as OwnSaleAmount
from UserMaster UM
left join SalesMaster SM on SM.UserId = UM.UserId -- Missed requirement1
left join SalesProducts SP on SP.SaleId = SM.SalesId -- Missed requirement1
where UM.UserId = 2 -- Userid of logged in user which will act as anchor member
group by UM.UserId ,UM.AddedBy -- for later subqueries
union all
select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount
from UserMaster UM
join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
join SalesMaster SM on SM.UserId = UM.UserId
join SalesProducts SP on SP.SaleId = SM.SalesId
),
tbldistinctOwnSaleAmount as
(
select distinct UserId, AddedBy, OwnSaleAmount
from tblOwnSaleAmount
) ,
tblTotalOwnSaleAmount as
(
select OSA.UserId,OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
from tbldistinctOwnSaleAmount OSA
group by OSA.UserId ,OSA.AddedBy
)
select OSA.*
, TotalSalesAmount = isnull(
(
select sum( OSA1.OwnSaleAmount )
from tblTotalOwnSaleAmount OSA1
where OSA1.UserId > OSA.UserId
), 0 )
+ OSA.OwnSaleAmount
from tblTotalOwnSaleAmount OSA
order by OSA.UserId
希望这有帮助!!!
[EDIT2]：更新了错过要求2的查询：
--2. IS it another requirement that user entries with status id = 2 should not be considered? -- Yes!!!
with tblOwnSaleAmount as
(
select UM.UserId, UM.AddedBy, sum( SM.Price*SP.Quantity ) as OwnSaleAmount
from UserMaster UM
left join SalesMaster SM on SM.UserId = UM.UserId and SM.statusID = 1-- Missed requirement1 and 2
left join SalesProducts SP on SP.SaleId = SM.SalesId -- Missed requirement1
where UM.UserId = 2 -- Userid of logged in user which will act as anchor member
group by UM.UserId ,UM.AddedBy -- for later subqueries
union all
select UM.UserId, UM.AddedBy,
case when SM.statusID = 1 then ( SM.Price*SP.Quantity )
else 0 end as OwnSaleAmount --Missed Requirement 2.
from UserMaster UM
join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
join SalesMaster SM on SM.UserId = UM.UserId
join SalesProducts SP on SP.SaleId = SM.SalesId
),
tbldistinctOwnSaleAmount as
(
select distinct UserId, AddedBy, OwnSaleAmount
from tblOwnSaleAmount
) ,
tblTotalOwnSaleAmount as
(
select OSA.UserId,OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
from tbldistinctOwnSaleAmount OSA
group by OSA.UserId ,OSA.AddedBy
)
select OSA.*
, TotalSalesAmount = isnull(
(
select sum( OSA1.OwnSaleAmount )
from tblTotalOwnSaleAmount OSA1
where OSA1.UserId > OSA.UserId
), 0 )
+ OSA.OwnSaleAmount
from tblTotalOwnSaleAmount OSA
order by OSA.UserId
要获得正确的结果，您需要更新锚表的on谓词，然后为其他递归表添加case语句。