将每行文件读入数组

时间:2013-10-04 04:50:55

标签: c arrays string file-io

我正在读取一个文件,并希望将每一行放入数组中的字符串中。文件的长度是任意的,每行的长度是任意的(虽然假设它将少于100个字符)。

这是我得到的,而不是编译。基本上这是一个字符数组的数组,对吧?所以不应该是char** words = (**char)malloc(sizeof(*char));

#include <stdio.h>
#include <stdlib.h>

int main(){


 int BUFSIZE = 32767;//max number of lines to read
 char** words = (**char)malloc(sizeof(*char));//gives error: expected expression before 'char'
 FILE *fp = fopen("coll.txt", "r");
 if (fp == 0){
        fprintf(stderr, "Error opening file");
        exit(1);
 }

int i = 0;
words[i] = malloc(BUFSIZE);
while(fscanf(fp, "%100s", words[i]) == 1)//no line will be longer than 100
{
        i++;
        words[i] = realloc(words, sizeof(char*)*i);
 }

 int j;
 for(j = 0; j < i; j++)
    printf("%s\n", words);

 return 0;
}

注意:我读过“Reading from a file and storing in array”,但它没有回答我的问题。

2 个答案:

答案 0 :(得分:13)

您的计划存在一些问题。 realloc()语句未正确使用。我也更喜欢fgets()来获取一条线。这是我的解决方案。这也使用realloc()来增加缓冲行的分配,这样你既不必事先知道行数,也不必两次读取文件(以这种方式更快)。当您不知道需要提前分配多少内存时,这是一种常用的技术。

#include <stdio.h>
#include <stdlib.h>

int main(void)

    {
    int lines_allocated = 128;
    int max_line_len = 100;

    /* Allocate lines of text */
    char **words = (char **)malloc(sizeof(char*)*lines_allocated);
    if (words==NULL)
        {
        fprintf(stderr,"Out of memory (1).\n");
        exit(1);
        }

    FILE *fp = fopen("coll.txt", "r");
    if (fp == NULL)
        {
        fprintf(stderr,"Error opening file.\n");
        exit(2);
        }

    int i;
    for (i=0;1;i++)
        {
        int j;

        /* Have we gone over our line allocation? */
        if (i >= lines_allocated)
            {
            int new_size;

            /* Double our allocation and re-allocate */
            new_size = lines_allocated*2;
            words = (char **)realloc(words,sizeof(char*)*new_size);
            if (words==NULL)
                {
                fprintf(stderr,"Out of memory.\n");
                exit(3);
                }
            lines_allocated = new_size;
            }
        /* Allocate space for the next line */
        words[i] = malloc(max_line_len);
        if (words[i]==NULL)
            {
            fprintf(stderr,"Out of memory (3).\n");
            exit(4);
            }
        if (fgets(words[i],max_line_len-1,fp)==NULL)
            break;

        /* Get rid of CR or LF at end of line */
        for (j=strlen(words[i])-1;j>=0 && (words[i][j]=='\n' || words[i][j]=='\r');j--)
            ;
        words[i][j+1]='\0';
        }
    /* Close file */
    fclose(fp);

    int j;
    for(j = 0; j < i; j++)
        printf("%s\n", words[j]);

    /* Good practice to free memory */
    for (;i>=0;i--)
        free(words[i]);
    free(words);
    return 0;
    }

答案 1 :(得分:0)

您应该更改以下行:

char** words = (**char)malloc(sizeof(*char));

进入这个:

char** words=(char **)malloc(sizeof(char *)*Max_Lines);