Question

我遇到了一个非常棘手的C ++编译器错误。

当我构造一个用作参数的字符串时，它在调用常规方法时起作用。例如。 printThisString(string(charPtr));

如果构造函数的参数是char*，则在构造对象时不起作用。例如，MyObject a(string(argv[0]));如果参数是文字，它仍然有用。例如，MyObject b(string("hi"));

#include <iostream>
#include <string>

using namespace std;

void printString(string toPrint) {
    cout << toPrint << endl;
}

class MyObject {
    int blah;
public:
    void aMethod() {}
    MyObject (string myStr) {
        cout << myStr << endl;
    }
};

int main(int argc, char ** argv) {

string s1(argv[0]);
char * s2 = "C-style string"; // I realize this is bad style

printString(string("Hello world!")); // All of these work
printString(s1);
printString(string(s2));
printString(string(argv[0]));

MyObject mo1 (string("Hello world!")); // Valid
MyObject mo2 (s1); // Valid
MyObject mo3 (string(s2)); // Does not print
MyObject mo4 (string(argv[0])); // Does not print

mo1.aMethod();
mo2.aMethod();
mo3.aMethod(); // Error
mo4.aMethod(); // Error


return 0;
}

对于mo3和mo4，可以创建对象，但不能使用任何方法。它们的类型错误。似乎编译器认为它们是函数......

test.cpp: In function 'int main(int, char**)':
test.cpp:22:13: warning: deprecated conversion from string constant to 'char*' [-Wwrite-strings]
test.cpp:36:5: error: request for member 'aMethod' in 'mo3', which is of non-class type 'MyObject(std::string) {aka MyObject(std::basic_string<char>)}'
test.cpp:37:5: error: request for member 'aMethod' in 'mo4', which is of non-class type 'MyObject(std::string*) {aka MyObject(std::basic_string<char>*)}'

Answer 1

这只是most vexing parse的变体：mo3和mo4是函数声明而不是对象定义。您可以使用

解决问题

MyObject mo3 {string(s2)};
MyObject mo4 {string(argv[0])};

或

MyObject mo3 ((string(s2)));
MyObject mo4 ((string(argv[0])));

或

MyObject mo3 = MyObject(string(s2));
MyObject mo4 = MyObject(string(argv[0]));

或......

std :: string在Arguments中构造

1 个答案: