什么错误应该给代码我无法弄清楚这一点？

Question

$upload = new uploadObject('songs');  

$upload->title = $data['upload_data']['title'];
$upload->description = $data['upload_data']['description'];
$upload->tags = $data['upload_data']['tags'];

注意：未定义的变量$ data

Answer 1

您需要在顶部定义$data，例如..

$data="";
// then your other code