Question

我有以下gridview。

 <asp:GridView ID="gvMarks" runat="server" AutoGenerateColumns="false" 
   DataKeyNames="MarkId" Width="80%" onrowdatabound="gvMarks_RowDataBound" 
   ShowFooter="True" onrowcommand="gvMarks_RowCommand">
    <Columns>
        <asp:TemplateField>
            <HeaderTemplate>
                SubjectCode
            </HeaderTemplate>
          <FooterTemplate>
            <asp:DropDownList ID="dlSubjectCode" runat="server" width="100px" AutoPostBack="false"></asp:DropDownList>
          </FooterTemplate>
        </asp:TemplateField>
        <asp:TemplateField>
            <HeaderTemplate>
               Mark
            </HeaderTemplate>
              <FooterTemplate>
                <asp:TextBox ID="txtInternalMark" runat="server" ></asp:TextBox>
            </FooterTemplate>
        </asp:TemplateField>

        <asp:TemplateField>
            <HeaderTemplate>
              Insert
            </HeaderTemplate>
            <FooterTemplate>
                <asp:LinkButton ID="lnkInsert" runat="server" Text="Insert" 
                    CommandName="Insert" ></asp:LinkButton>
            </FooterTemplate>
        </asp:TemplateField>
    </Columns>
    <FooterStyle BackColor="White" ForeColor="#000066" />
    <RowStyle ForeColor="#000066" />
    <SelectedRowStyle BackColor="#669999" Font-Bold="True" ForeColor="White" />
    <PagerStyle BackColor="White" ForeColor="#000066" HorizontalAlign="Left" />
    <HeaderStyle BackColor="#006699" Font-Bold="True" ForeColor="White" />
</asp:GridView>

如果我在txtInternalMark中输入一些值，我不会在后面的代码中设置它的值。我将值设为“”。使用以下代码

if (e.CommandName.Equals("Insert"))
{
    TextBox txtInternalMark = (TextBox)gvMarks.FooterRow.FindControl("txtInternalMark");
    lblMessage.Text = txtInternalMark .Text;
}

任何人都可以帮助在代码隐藏中获取textbox的值。

Answer 1

海

string Ingredient = ((TextBox) gvMarks.FooterRow.FindControl("txtInternalMark")).Text;

 Response.Write(Ingredient);

如果不起作用，请将CausesValidation="False"添加到ur linkbutton lnkInsert

关注gridview中的footerrow

1 个答案: