如何计算item-qty
和当前代码: -
$q = $_POST['item-qty'];
$i = count($q);
$k = 0;
while ($k < $i) {
$select = 'SELECT * FROM location';
$query = $db->rq($select);
$price = $db->fetch($query);
if ($_POST['item-qty'][$k] < 3) {
$get = $price['normal_price'];
$price = $get * $_POST['item-qty'][$k];
$_SESSION['order'][$_POST['item-id'][$k]] = array(
"item-id" => $_POST['item-id'][$k],
"item-qty" => $_POST['item-qty'][$k],
"item-name" => $_POST['item-name'][$k],
"item-price" => $price,
);
} else {
$get = $price['member_price'];
$price = $get * $_POST['item-qty'][$k];
$_SESSION['order'][$_POST['item-id'][$k]] = array(
"item-id" => $_POST['item-id'][$k],
"item-qty" => $_POST['item-qty'][$k],
"item-name" => $_POST['item-name'][$k],
"item-price" => $price,
);
}
}
这里是数组输出
Array
(
[order] => Array
(
[1] => Array
(
[item-id] => 1
[item-qty] => 1
[item-name] => Adidas
[item-price] => 100
)
[2] => Array
(
[item-id] => 2
[item-qty] => 1
[item-name] => Nike
[item-price] => 150
)
)
)
问题:
item-qty
(在所有数组中)大于或等于3,如何实现其他代码将使用$price['member_price']
让我知道:)。
答案 0 :(得分:1)
我猜你的意思是所有东西的总项目数量?
$qty_sum = 0
foreach($_SESSION['order'] as $order){
$qty_sum += $order['item-qty'];
}