我有一个由6个形状的子图组成的图形(2,3)。我想删除所有内部刻度线,只有左侧和底侧显示刻度标签。
默认刻度线:
import matplotlib.pyplot as plt
import numpy as np
fig, ax = plt.subplots(2,3,
sharex = True,
sharey = True)
plt.subplots_adjust(hspace = 0,
wspace = 0)
产生这个:
看了无数的例子后,我设法删除了内部刻度线,但现在又出现了新的(额外的)刻度标签。我找到的用于删除刻度标签的解决方案不起作用,它们会删除所有x(或y)刻度标签,而不仅仅是指定的轴。
新代码:
import matplotlib.pyplot as plt
import numpy as np
fig, ax = plt.subplots(2,3,
sharex = True,
sharey = True)
plt.subplots_adjust(hspace = 0,
wspace = 0)
ax[0,0].xaxis.set_ticks_position('top')
ax[0,0].yaxis.set_ticks_position('left')
ax[0,1].xaxis.set_ticks_position('top')
ax[0,1].yaxis.set_ticks_position('none')
ax[0,2].xaxis.set_ticks_position('top')
ax[0,2].yaxis.set_ticks_position('right')
ax[1,0].xaxis.set_ticks_position('bottom')
ax[1,0].yaxis.set_ticks_position('left')
ax[1,1].xaxis.set_ticks_position('bottom')
ax[1,1].yaxis.set_ticks_position('none')
ax[1,2].xaxis.set_ticks_position('bottom')
ax[1,2].yaxis.set_ticks_position('right')
产生这个:
我想要的最终输出是:
请注意左侧和底部的标签,但周边有刻度标记。
答案 0 :(得分:4)
这适用于任意大小的网格。你的问题是你没有删除蜱,你只是将它们移到顶部:
import matplotlib.pyplot as plt
import numpy as np
Nrows = 2
Ncols = 3
fig, ax = plt.subplots(Nrows, Ncols,
sharex=True,
sharey=True)
plt.subplots_adjust(hspace=0,
wspace=0)
for i in range(Nrows):
for j in range(Ncols):
if i == 0:
ax[i,j].xaxis.set_ticks_position('top')
plt.setp(ax[i,j].get_xticklabels(), visible=False)
elif i == Nrows-1:
ax[i,j].xaxis.set_ticks_position('bottom')
else:
ax[i,j].xaxis.set_ticks_position('none')
if j == 0:
ax[i,j].yaxis.set_ticks_position('left')
elif j == Ncols-1:
ax[i,j].yaxis.set_ticks_position('right')
plt.setp(ax[i,j].get_yticklabels(), visible=False)
else:
ax[i,j].yaxis.set_ticks_position('none')
答案 1 :(得分:0)
下面的功能删除内轴刻度标签:
import matplotlib.pyplot as plt
import numpy as np
def remove_internal_ticks(ax,remove_x = True,remove_y = True):
'''Function removes ytick labels from all the subplots (ax) other than those on
the first column (provided remove_y=True) and all xtick labels from subplots (ax)
other than those on the bottom row (provided remove_x=True).'''
nrows = np.size(ax,0)
ncols = np.size(ax,1)
for i in range(nrows):
for j in range(ncols):
if remove_x and i<nrows-1:
plt.setp(ax[i,j].get_xticklabels(), visible=False)
if remove_y and j>0:
plt.setp(ax[i,j].get_yticklabels(), visible=False)