Question

我的Android应用程序正在调用WCF Web服务但我无法发送获取请求：

这是我的WCF合约

[OperationContract]
    [WebGet(UriTemplate = "ValidateLogin/{userId}/{password}",
        ResponseFormat = WebMessageFormat.Json,
        RequestFormat = WebMessageFormat.Json,
        BodyStyle = WebMessageBodyStyle.Wrapped)]
    LoginValidation ValidateLogin(string userId, string password);

我在我的Android应用程序上调用它

public String ValidateLogin(ArrayList<NameValuePair> httgetArgs){

    String result = "";

    String url = "http://10.0.2.2/WSCom.svc/ValidateLogin";
    InputStream is = null;
    try {
        HttpClient httpclient = new DefaultHttpClient();
        setparameters(url , new UrlEncodedFormEntity(httgetArgs));

        HttpGet httget = new HttpGet(url);

        httget.setHeader("Accept", "application/json");
        httget.setHeader("Content-Type", "application/json");


        HttpResponse response = httpclient.execute(httget);

        HttpEntity entity = response.getEntity();

        is = entity.getContent();

    } 
        catch (Exception e) {
        result = e.toString();
    }

    try {
        result = readStream(is); 

        is.close();
    } 
    catch (Exception e) {

        result = e.toString();
    }
    return (result);
    }

但是我得到了错误

合同'IWSCom'中的'ValidateLogin'操作使用GET，但也有body参数'userId'。 GET操作不能有一个正文。将参数'userId'设为UriTemplate参数，或从WebGetAttribute切换到WebInvokeAttribute

Answer 1

您需要具有以下网址

String url = "http://10.0.2.2/WSCom.svc/ValidateLogin/YourUserId/Password";

当你在url中传递数据时，你不需要使用

setparameters(url , new UrlEncodedFormEntity(httgetArgs));

Answer 2

String user = "";
String pass = "";
String url = "http://10.0.2.2/WSCom.svc/ValidateLogin/" + user + "/" + pass;

Android调用WCF Web服务时，GET操作不会出现正文错误

2 个答案: