我正在使用javascript在我的应用中实现滑动功能,在演示中跟随此链接http://www.photoswipe.com/latest/examples/01-default.html
,代码完美无缺,但在将其添加到我的项目后,图像的滑动无法正常工作。请帮帮我..
<!DOCTYPE html>
<html>
<head>
<title>PhotoSwipe</title>
<meta name="author" content="Ste Brennan - Code Computerlove - http://www.codecomputerlove.com/" />
<meta content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=0;" name="viewport" />
<meta name="apple-mobile-web-app-capable" content="yes" />
<link href="styles.css" type="text/css" rel="stylesheet" />
<link href="../photoswipe.css" type="text/css" rel="stylesheet" />
<script type="text/javascript" src="../libs/klass.min.js"></script>
<script type="text/javascript" src="../code.photoswipe-3.0.5.min.js"></script>
<script type="text/javascript">
(function(window, PhotoSwipe){
document.addEventListener('DOMContentLoaded', function(){
var
options = {},
instance = PhotoSwipe.attach( window.document.querySelectorAll('#Gallery a'), options );
}, false);
}(window, window.Code.PhotoSwipe));
</script>
</head>
<body>
<div id="Header">
<a href="http://www.codecomputerlove.com"><img src="images/codecomputerlovelogo.gif" width="230" height="48" alt="Code Computerlove" /> </a>
</div>
<div id="MainContent">
<div class="page-content">
<h1>PhotoSwipe</h1>
</div>
<ul id="Gallery" class="gallery">
<li><a href="images/full/001.jpg"><img src="images/thumb/001.jpg" alt="Image 001" /></a></li>
<li><a href="images/full/002.jpg"><img src="images/thumb/002.jpg" alt="Image 002" /></a></li>
<li><a href="images/full/003.jpg"><img src="images/thumb/003.jpg" alt="Image 003" /></a></li>
<li><a href="images/full/004.jpg"><img src="images/thumb/004.jpg" alt="Image 004" /></a></li>
<li><a href="images/full/005.jpg"><img src="images/thumb/005.jpg" alt="Image 005" /></a></li>
<li><a href="images/full/006.jpg"><img src="images/thumb/006.jpg" alt="Image 006" /></a></li>
<li><a href="images/full/007.jpg"><img src="images/thumb/007.jpg" alt="Image 007" /></a></li>
<li><a href="images/full/008.jpg"><img src="images/thumb/008.jpg" alt="Image 008" /></a></li>
<li><a href="images/full/009.jpg"><img src="images/thumb/009.jpg" alt="Image 009" /></a></li>
<li><a href="images/full/010.jpg"><img src="images/thumb/010.jpg" alt="Image 010" /></a></li>
<li><a href="images/full/011.jpg"><img src="images/thumb/011.jpg" alt="Image 011" /></a></li>
<li><a href="images/full/012.jpg"><img src="images/thumb/012.jpg" alt="Image 012" /></a></li>
<li><a href="images/full/013.jpg"><img src="images/thumb/013.jpg" alt="Image 013" /></a></li>
</ul>
</div>
</body>
</html>
答案 0 :(得分:0)
以下应该这样做。我在多个项目中使用它。
<script type="text/javascript">
// other functions
document.addEventListener("deviceready", onDeviceReady, true);
function onDeviceReady() {
// related functions
$("#Gallery a").photoSwipe();
}
</script>