Question

我试图从我的主体代码中排除我的二次方程式，现在它返回的是十六进制数字......数字是相当随机返回的，它们在运行程序时每3-10次更改一次值，即使变量是不变的。这远远超过了我对C ++的了解。

理想情况下，我想在双数据类型和基数10中返回二次方程的根。

最后一个注释掉的位只是为了向您展示我最初做过的事情，尽管多数是多余的。

提前致谢。

#include <iostream>
#include <cmath>
using namespace std;


double a,b,c,bsq;

double quadpos() {

    double quadpos = (-b+(sqrt((bsq)-4.0*a*c)))/(2.0*a);

    double a=1.0,b=2.0,c=1.0;
    double bsq = pow(2.0,2);

    return quadpos;
}

double quadneg() {

    double quadneg = (-b-(sqrt((bsq)-4.0*a*c)))/(2.0*a);
    return quadneg;
}


int main() {
    // 4a)
    cout << /*" - Question 4 - \n\n" << "Part A\n" << */quadpos << "\n" << quadneg << std::endl;

    /*float a = 5.0, b = 7.0, c = -8.0;
    int bsq;
    bsq = pow(b,2);
    double quadpos = (-b+(sqrt((bsq)-4.0*a*c)))/(2.0*a), quadneg = (-b-(sqrt((bsq)-4.0*a*c)))/(2.0*a);

    cout << a << "\n" << b << "\n" << c << "\n" << bsq << "\n" << quadpos << "\n" << quadneg << endl;
    The above line is used for troubleshooting

    cout << "The roots of the quadratic equation 5x^2 + 7x - 8 are " << quadpos << " and " << quadneg << ".\n" << "The roots are the values of the x variable when the equation, 5x^2 + 7x - 8 is equal to 0.\n" << endl;
    */
}

Answer 1

cout << /* ... */ quadpos << "\n" << quadneg << std::endl;
                       ^^^^ ?

您正在直接打印函数并获取其地址（在此上下文中它们被解释为函数指针）。而不是quadpos，而是quadpos()。

来自c的随机十六进制答案

1 个答案: